If i = prt, which equation is equivalent to t?

Mathematics

2 answers:

horsena [70]3 years ago

8 0

i = prt
t = i/(pr)
.........................

quester [9]3 years ago

5 0

Answer:

The value of $t = \frac{i}{pr}$

Step-by-step explanation:

Solve for t :- $i = prt$

Division property of equality states that you divide the same number to both sides of an equation.

Divide both sides by pr we get;

$\frac{i}{pr}=\frac{prt}{pr}$

Simplify:

$t = \frac{i}{pr}$

Therefore, the value of t is, $t = \frac{i}{pr}$

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Infinite over E n=1 4(0.5)^n-1

yan [13]

Answer:

S = 8

Step-by-step explanation:

An infinite geometric series is defined as limit of partial sum of geometric sequences. Therefore, to find the infinite sum, we have to find the partial sum first then input limit approaches infinity.

However, fortunately, the infinite geometric series has already set up for you. It’s got the formula for itself which is:

$\displaystyle \large{\lim_{n\to \infty} S_n = \dfrac{a_1}{1-r}}$

We can also write in summation notation rather S-term as:

$\displaystyle \large{\sum_{n=1}^\infty a_1r^{n-1} = \dfrac{a_1}{1-r}}$

Keep in mind that these only work for when |r| < 1 or else it will diverge.

Also, how fortunately, the given summation fits the formula pattern so we do not have to do anything but simply apply the formula in.

$\displaystyle \large{\sum_{n=1}^\infty 4(0.5)^{n-1} = \dfrac{4}{1-0.5}}\\\\\displaystyle \large{\sum_{n=1}^\infty 4(0.5)^{n-1} = \dfrac{4}{0.5}}\\\\\displaystyle \large{\sum_{n=1}^\infty 4(0.5)^{n-1} = 8}$