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r-ruslan [8.4K]
3 years ago
13

Please help! geometry :/

Mathematics
1 answer:
meriva3 years ago
8 0
The Value of U is U=13
You might be interested in
Marcus is laying pavers to build a patio in his backyard. Each square paver measures 2 feet on each side. He would like the pati
vaieri [72.5K]

Answer:

20 pavers

Step-by-step explanation:

step 1

Find the area of the rectangular patio

The area of a rectangle is equal to

A=LW

we have

L=20\ ft\\W=4\ ft

substitute

A=(20)(4)=80\ ft^2

step 2

Find the area of one square paver

The area of a square is equal to

A=s^2

we have

s=2\ ft ---> length side of the paver

substitute

A=2^2=4\ ft^2

step 3

Divide the area of the rectangular patio by the area of one paver to find out the number of pavers needed

80/4=20\ pavers

4 0
3 years ago
13
luda_lava [24]

Answer:

0.028x-6-0.48x-2+0.552x

(0.028-0.48+0.552)x-6-2

0.1x-8

8 0
3 years ago
The multiplicative inverse of -3/11 × 1/5 is​
Agata [3.3K]

Answer:

-55/3

Step-by-step explanation:

-3/11 x1/5

-3/55

Multiplicative inverse means Reciprocal of -3/55 [That means the numerator goes to the denominator and the denominator to the numerator]

=> -55/3

4 0
3 years ago
Lena is 10 years old. She asks her dad how old he is. He tells her that the lcm of their ages is 14 times the hcf of their ages.
strojnjashka [21]

Answer:

  35

Step-by-step explanation:

Let x represent the HCF of the ages. Then we can have ax = 10 represent Lena's age, and bx can represent her dad's age.

The LCM will be abx = 14x, so we have ab = 14.

Factors of 14 are 1·14 and 2·7. Since the ratio of ages is between 30/10 = 3 and 45/10 = 4.5, we must have b/a in that range. This will be the case for ...

  a=2, b=7

For a=2 and ax=10, we have x=5.

The dad's age is bx = 7·5 = 35.

5 0
3 years ago
Please help and add explanation:)
Anni [7]

Answer:

NO

Step-by-step explanation:

The above image shows two triangles. if we look at the top triangle, we notice it's two sides are equal (16 and 16). We therefore have an isosceles right triangle.

looking the second triangle, we notice that one side is 39, the other 40. Since these are the two sides joined at the point of intersection for the two images, and since 39 does not equal 40, the second triangle cannot be an isosceles right triangle. We conclude that the two triangles are not similar.

8 0
3 years ago
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