You just have to go 7x28=[7x20]+[7x8]=196
Answer:
An example of when a continuity correction factor can be used is in finding the number of tails in 50 tosses of a coin within a given range .
and continuity correction factor is used when a continuous probability distribution is used on a discrete probability distribution
Step-by-step explanation:
An example of when a continuity correction factor can be used is in finding the number of tails in 50 tosses of a coin within a given range .
continuity correction factor is used when a continuous probability distribution is used on a discrete probability distribution, continuity correction factor creates an adjustment on a discrete distribution while using a continuous distribution
I think it would be around 7 lbs
(i could be wrong but i think this is about right)
Answer:
Step-by-step explanation:
Given:
elongation, x = 0.50 in
Force, f = 9000 lb
Young modulus, E = 10,000,000 psi
Maximum Stress, Sm = 30000 psi
Length, L = 16 ft
Converting ft to in,
12 in = 1 ft
=16 × 12 = 192 in
Young modulus, E = stress/strain
Stress = force/area, A
Strain = elongation, x/Length, L
E = f × L/A × E
1 × 10^7 = stress/(0.5/16)
= 26041.7 psi
Minimum stress = 26041.7 psi
Maximum stress = 30,000 psi
Stress = force/area
Area = 9000/26041.7
= 0.3456 in^2
Stress = force/area
Area = 9000/30000
= 0.3 in^2
Using minimum area of 0.3 in^2,
A = (pi/4)(d^2)
0.3 in^2 = (pi/4)(d^2)
d = 0.618 inches
diameter, d = 0.618 inches
Answer:
See below
Step-by-step explanation:
4 more than 3: 3 + 4 = 7
5 out of 9: 5/9
the sum of 6 and 8: 6 + 8 = 14
10 less than 14: 14 - 10 = 4
the product of 3 and 4: 3 * 4 = 12
the ratio of 2 to 3: 2/3
10 decreased by 8: 10 - 8 = 2
the quotient of 23 and 25: 23/23
3 increased by 33: 3 + 33 = 36
50% of 32: 50% * 32 = 0.5 * 32 = 16
