All categories

3 years ago

Find the value of n in n5=32

Mathematics

2 answers:

g100num [7]3 years ago

6 0

Answer:

Step-by-step explanation:

$n^5=32$

If you take the fifth root of both sides, you get n=2. You also know that n can't be 2 or -2, because when you raise a negative number to an odd numbered exponent, you get a negative and not a positive number. Hope this helps!

timama [110]3 years ago

3 0

Answer:

Step-by-step explanation:

n^{5}=32=2×2×2×2×2=2^5

n=2

You might be interested in

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

3 years ago

Plz answer fast for this question

torisob [31]

170 cm. The unknown length on the left is 21 cm

5 0

3 years ago

Can someone solve this ASAP.

Dimas [21]

Answer:

where's the picture?

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

9 x {[14/2+(4-1)]-8}

valentina_108 [34]

Answer:

Step-by-step explanation:

order of operations

6 0

3 years ago

The sum of 4 consecutive even integers is -4. What are the integers?

Lina20 [59]

Answer:

-4, -2, 0, 2

Step-by-step explanation:

the expression for the integers are; x, x +2, x + 4, x + 6

4x + 12 = -4

4x = -16

x = - 4

your integers are; -4, -2, 0, 2

if you add those your answer will be -4

8 0

3 years ago