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REY [17]
3 years ago
6

If Cade shoots 275 free throw baskets in 2 hours, about how many can he shoot in 5 hours.

Mathematics
2 answers:
Blababa [14]3 years ago
7 0
He/she can shoot an average of 687.5 in 5 hours, or 137.5 per hour
Ivanshal [37]3 years ago
5 0
Cade will shoot 688 baskets
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Match each subtraction problem on the left with the equivalent simplified expression on the right.
Ahat [919]

Answer:

A-3, B-4, C-1, D-2

Step-by-step explanation:

A:

  • 5x-(3x+1)
  • Expand, 5x-3x-1
  • Combine like terms, 2x-1

B:

  • 5x-(-3x-1)
  • Expand, 5x+3x+1
  • Combine like terms, 8x+1

C:

  • -5x-(3x+1)
  • Expand, -5x-3x-1
  • Combine like terms, -8x-1

D:

  • -5x-(-3x-1)
  • Expand, -5x+3x+1
  • Combine like terms, -2x+1

4 0
3 years ago
You are hired to work at quickie-mart and will be paid $9.50 per hour 1. Write an income function that describes the amount of m
zzz [600]

Answer:

f(x)=nx

or

f(x)=9.50x

Step-by-step explanation:

Let x be the amount of hours and n be the hourly rate (9.50).

f(x)=nx

or if you prefer to use 9.50 instead of n, the function would be:

f(x)=9.50x

3 0
3 years ago
The value of a car is $ 16,000 and depreciating at a rate of 11% per year. Write an
Mandarinka [93]
Answer- 16,000(0.88)t.
6 0
3 years ago
The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
Find an antiderivative F(x) with F'(x) = f(x) = 11+(21x^2)+(21x^6) and F(1)=0
Sunny_sXe [5.5K]
11x + 7x^3 + 3x^7 - 21
8 0
2 years ago
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