This problem can be solved by using ideal gas equation PV=nRT. The unit used in the numbers is already matched so you don't need to convert any of them. The calculation would be:
PV= nRT
102.3 kPa * V = 0.00831 mol *298.15 K* (8.314 L*kPa/mol*K) V= 20.60 L-kPa / 102.3 kPa V= 0.201358 L
Answer:
T₂ = 251.6 K
Explanation:
Given data:
Initial temperature = 41°C
Initial volume = 4.87 L
Final volume = 6.08 L
Final temperature = ?
Solution:
Initial temperature = 41°C (41+273.15 = 314.15 K)
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = V₂T₁ /V₁
T₂ = 4.87 L × 314.15 K / 6.08 L
T₂ = 1529.9 L.K / 6.08 L
T₂ = 251.6 K
Answer: Number of atoms in 
of radon gas (radon atoms) at the same temperature and pressure is 
Explanation:
According to avogadro's law, volume of a gas is directly proportional to the number of moles present when temperature and pressure is constant.:
= moles of hydrogen gas = 
= moles of radon gas = ?
Thus the number of atoms in of radon gas (radon atoms) at the same temperature and pressure is
<span>They are both <em>mixtures</em> and are dissolved. The difference is that a <em>solution</em> is mixed more then a <em><span>mixture</span></em></span>
