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NikAS [45]
2 years ago
11

Compare Rutherford’s model of the atom with Bohr’s model.

Chemistry
1 answer:
BlackZzzverrR [31]2 years ago
8 0

it described a nucleus surrounded by a large volume of space.

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From the lists of available reagents select the one(s) you would use to in a preparation of acetophenone (phenyl methyl ketone)
VARVARA [1.3K]

Answer:

Step 1) hydrolysis using NaOH/H2O to form benzylalcohol

Step2) oxidation to Carboxylic acid using KMnO4 followed by decarboxylation to form benzene

3) friedel craft acylation using CH3COCl/AlCl3

Explanation:

The above 3 steps will yield acetophenone from methylbenzoate

3 0
2 years ago
Classify the following as homogeneous or heterogeneous mixtures, or pure
victus00 [196]

Explanation:

Sugar -  Pure substance

Magnesium Ribbon - Pure Substance

Vegetable soup  Heterogeneous mixture

Bath oil - Homogeneous mixture

Tin of assorted biscuits - Heterogeneous mixture

Peanuts and raisins - Heterogeneous mixture

Copper wire - Pure Substance

Bicarbonate of soda  (Baking soda)​ - Pure Substance

6 0
2 years ago
Consider the energy transfers and transformations that occur when a person rides a bicycle. Describe thi
cupoosta [38]

Answer:

1.B

2.A

3.B

Explanation:

7 0
2 years ago
Read 2 more answers
Is a specimen a monocot or dicot
den301095 [7]
Monocots<span> have only one seed leaf inside the seed coat. It is often only a thin leaf, because the endosperm to feed the new plant is not inside the seed leaf. </span>Dicots <span>have two seed leaves inside the seed coat. They are usually rounded and fat, because they contain the endosperm to feed the embryo plant.
</span><span>
</span>
7 0
2 years ago
A sample of gas occupies a volume of 27 mL at a temperature of 161K. What is the volume of the temperature if raised to 343K?
d1i1m1o1n [39]

Answer: The  volume is 57.52 mL if the temperature if raised to 343K.

Explanation:

Given: V_{1} = 27 mL,       T_{1} = 161 K

V_{2} = ?,        T_{2} = 343 K

According to Charles law, at constant pressure the volume of an ideal gas is directly proportional to temperature.

Formula used is as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{27 mL}{161 K} = \frac{V_{2}}{343 K}\\V_{2} = 57.52 mL

Thus, we can conclude that volume is 57.52 mL if the temperature if raised to 343K.

4 0
3 years ago
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