<span>30 hours
For this problem, going to assume that the actual flow rate for both pipes is constant for the entire duration of either filling or emptying the pool. The pipe to fill the pool I'll consider to have a value of 1/12 while the drain that empties the pool will have a value of 1/20. With those values, the equation that expresses how many hour it will take to fill the pool while the drain is open becomes:
X(1/12 - 1/20) = 1
Now solve for X
X(5/60 - 3/60) = 1
X(2/60) = 1
X(1/30) = 1
X/30 = 1
X = 30
To check the answer, let's see how much water would have been added over 30 hours.
30/12 = 2.5
So 2 and a half pools worth of water would have been added. Now how much would be removed?
30/20 = 1.5
And 1 and half pools worth would have been removed. So the amount left in the pool is
2.5 - 1.5 = 1
And that's exactly the amount needed.</span>
m=1 is the answer for that question
Answer:
option D
. 254.34cm^2
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
The options are:
A
. 56.52cm^2
B
. 141.30cm^2
C
. 1,017.36cm^2
D
. 254.34cm^2
step 1
Find the diameter of the largest circle
we know that
The diameter of the largest circle is equal to the sum of the diameter of the two inside circles
so

step 2
Find the area of the largest circle
we know that
The area of the circle is given by the formula

we have
----> the radius is half the diameter
assume

substitute

Answer/Step-by-step explanation:
Volume of a cylinder is given as V = πr²h
Where,
radius (r) = 6 cm
height (h) = 8 cm
Plug in the values
V = π*6²*8
V = π*36*8
V = π*288
V = 288π cm³ or 904.78 cm³