When graphing Y=3X-5 you want to start looking at the Y axis or the vertical line that goes up and down. You need to draw your first point or dot on the vertical line starting at negative five (-5). Then you start to go up 3 boxes and over 1 box or to the right one box because the equation has 3x in it . So after starting at negative 5 you want to travel up 3 and over 1, up three and over 1, do this until your graph can no longer go on or is not bug enough. Did i answer your question?
The demoin is all real numbers greater than 6
Answer:
0, 2, 4, 6, 8
Step-by-step explanation:
the first couple of multiples of 2 are...
2, 4, 6, 8, 10
the last digits are 0, 2, 4, 6, 8...
so, 0, 2, 4, 6, 8 are the last digits!
Complete question :
Members of the swim team want to wash their hair. The bathroom has less than 5600 liters of water and at most 2.5 liters of shampoo. 70L+ 60S < 5600 represents the number of long-haired members L and short-haired members S who can wash their hair with less than 5600 liters of water. 0.02L + 0.01S < or equal to 2.5 represents the number of long-haired members and short-haired members who can wash their hair with at most 2.5 liters of shampoo. Does the bathroom have enough water and shampoo for 8 long-haired members and 7 short -haired members?
Answer:
Yes , there is enough water and shampoo
Step-by-step explanation:
Given that:
Number of long and short hair member who can wash their hair with less than 5600 litres of water.
70L+ 60S < 5600
Number of long and short hair member who can wash their hair with at most 2.5 litres of shampoo
0.02L + 0.01S ≤ 2.5
To check if bathroom has enough water and shampoo for 8 long haired and 7 short haired members.
Water check:
70L+ 60S < 5600
L = 8 ; S = 7
70(8) + 60(7) < 5600
560 + 420 < 5600
980 < 5600
Inequality constraint is satisfied ; There is enough water.
Shampoo check:
0.02L + 0.01S ≤ 2.5
L = 8 ; S = 7
0.02(8) + 0.01(7) ≤ 2.5
0.16 + 0.07 ≤ 2.5
0.23 ≤ 2.5
Inequality constraint is satisfied ; There is enough shampoo
Answer: 240 students
Explanation:
320 ÷ 8 = 40 (40 groups of 8)
40 x 6 = 240