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3 years ago

8

Please don’t report I need help. I’m going to be a high school sophomore next fall and I’m selecting my courses should I take Ge

ometry I or Algebra II?????

2 answers:

Mama L [17]3 years ago

6 0

Geometry l, It should be easier, if you want to take a harder class that will help you more towards graduating take Algebra ll

nata0808 [166]3 years ago

5 0

Answer:

I would say geometry. its easier

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Please help . I’ll mark you as brainliest if correct!!!

damaskus [11]

Answer:10 Seconds

Step-by-step explanation:

s=1600 ft

t=√(s) /4

t=√(1600)/4

t=40/4

t=10 seconds

8 0

3 years ago

Rewrite the following expression.

faust18 [17]

We have been given the expression

$x^{\frac{9}{7}}$

We have the exponent rule

$x^{\frac{a}{b}}= x^{a^{(\frac{1}{b})}}$

Using this rule, we have

$x^{\frac{9}{7}}= x^{9^{(\frac{1}{7})}}$

Now, using the fact that $x^{\frac{1}{n}}=\sqrt[n]{x}$ , we get

$x^{\frac{9}{7}}= \sqrt[7]{x^9}\\
\\
x^{\frac{9}{7}}=\sqrt[7]{x^7\times x^2}\\
\\
x^{\frac{9}{7}}=x\sqrt[7]{x^2}$

D is the correct option.

6 0

3 years ago

Read 2 more answers

(21-6)/3 how much money each one will make

wolverine [178]

Answer:

5

answer

answer

answer

answer

3 0

3 years ago

Type the numerical answer ONLY. (no spaces)

Fantom [35]

Answer:

98

Step-by-step explanation:

Mathematically, when we add all the angles of a triangle, we get 180

Thus;

x + 1 + 2x-2+ 3x-5 = 180

6x-6 = 180

6x = 186

x = 186/6

x = 31

so the measure of the biggest angle is 3x -5

= 3(31) + 5 = 93 + 5 = 98

7 0

3 years ago

A rock is thrown upward with an initial velocity of 16 ft/s from an initial height of 5 ft. How much time does it take for the r

Bogdan [553]

Check the picture below.

so it hits the ground when y = 0, thus

$\bf ~~~~~~\textit{initial velocity}\\\\
\begin{array}{llll}
~~~~~~\textit{in feet}\\\\
h(t) = -16t^2+v_ot+h_o
\end{array} 
\quad 
\begin{cases}
v_o=\stackrel{16}{\textit{initial velocity of the object}}\\\\
h_o=\stackrel{5}{\textit{initial height of the object}}\\\\
h=\stackrel{}{\textit{height of the object at "t" seconds}}
\end{cases}$

$\bf h(t)=-16t^2+16t+5\implies \stackrel{h(t)}{0}=-16t^2+16t+5
\\\\\\
16t^2-16t-5=0\implies (4t+1)(4t-5)=0\\\\
-------------------------------\\\\
4t+1=0\implies 4t=-1\implies t=-\cfrac{1}{4}\\\\
-------------------------------\\\\
4t-5=0\implies 4t=5\implies t=\cfrac{5}{4}\implies \boxed{t=1\frac{1}{4}}$

since "t" is seconds it took, it can't be a negative amount.

5 0

3 years ago