Answer:
21
Step-by-step explanation:
if v=2
then uw=21
because 6/2=3, and
14/2=7
3x7=21
If R is between Q and S then QR+RS=QS
given
QR=x+4
RS=3x-1
and QS=27
x+4+3x-1=27
combine like terms
4x+3=27
minus 3 both sides
4x=24
divide both sides by 4
x=6
sub back
QR=x+4
QR=6+4
QR=10
RS=3x-1
RS=3(6)-1
RS=18-1
RS=17
x=6
QR=10
RS=17
The property of real numbers illustrated by the equation 16(3t+4v)=48t+ 64v.
Therefore, the answer is: Distributive property.
As you can see, you have the equation 16(3t+4v), and when you apply the Distributive property, you obtain:
16(3t+4v)
(16)(3t)+(16)(4v)
48t+64v
Answer:
x = 11
Step-by-step explanation:
The relationship between the sine and cosine functions can be written as ...
sin(x) = cos(90 -x)
sin(A) = cos(90 -A) = cos(B) . . . . substituting the given values
Equating arguments of the cosine function, we have ...
90 -(3x+4) = 8x -35
86 -3x = 8x -35
86 +35 = 8x +3x . . . . . add 3x+35 to both sides
121 = 11x . . . . . . . . . . . . collect terms
121/11 = x = 11 . . . . . . . . divide by 11
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<em>Comment on the solution</em>
There are other applicable relationships between sine and cosine as well. The result is that there are many solutions to this equation. One set is ...
11 +(32 8/11)k . . . for any integer k
Another set is ...
61.8 +72k . . . . . for any integer k
First, underline the key numbers
n=Perfect Quizzes last quarter
x=School record
n+3
3•2=x
Now we solve that
3•2=6
Now we know, x=6
If the record (6) is 3 times the number of spelling quizzes Hannah scored perfectly last quarter (n), then we know we have to divide the record (6) by 3 to know how many perfect quizzes were from last quarter.
6/3=2 so, n=2
The number of perfectly scored quizzes from last quarter is 2.