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Nookie1986 [14]
3 years ago
11

What types of chemical bonds?​

Chemistry
1 answer:
DaniilM [7]3 years ago
7 0

Answer:

I am confused as to what you're asking.

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In which list are the elements arranged in order of increasing atomic mass?(1) Cl, K, Ar (3) Te, I, Xe(2) Fe, Co, Ni (4) Ne, F,
galina1969 [7]
Answer: 1

1.Cl K Ar is in order

2.Fe Co Ni isn't in order

3.Te I Xe isn't in order

4.Ne F Na isn't in order
4 0
3 years ago
A chemist mixes 71.1 g of carbon tetrachloride with 65.4 g of isopropenylbenzene and 4.02 g of 2-ethyltoluene. Calculate the per
-Dominant- [34]

Answer:

%  Carbon tetrachloride = 50.6 %

% isopropenylbenzene = 46.5 %

% 2-ethyltoluene = 2.9%

Explanation:

Step 1: Data given

A mixture contains:

71.1 grams of Carbon tetrachloride (CCl4)

65.4 grams of isopropenylbenzene (C9H10)

4.02 grams of 2-ethyltoluene (C9H12)

Step 2: Calculate total mass

Total mass = mass CCl4 + mass C9H10 + mass C9H12

Totam mass = 71.1g + 65.4g + 4.02g

Total mass = 140.52 grams

Step 3: Calculate % of each component:

% component = (mass component/ total mass) *100%

%  Carbon tetrachloride = (71.1 / 140.52) *100 %

%  Carbon tetrachloride = 50.6 %

% isopropenylbenzene = (65.4 / 140.52) *100%

% isopropenylbenzene = 46.5 %

% 2-ethyltoluene = (4.02/140.52) *100%

% 2-ethyltoluene = 2.9%

50.6% + 46.5% + 2.9% = 100%

5 0
3 years ago
Read 2 more answers
At S?fndnfnfnfxmckfkffkfkfk ckfkfkfkfkfkv kfflfmcmc
IRINA_888 [86]

Answer:

what?

Explanation:

3 0
3 years ago
What scientist designed an experiment that enabled the first successful detection of an individual subatomic particle?
damaskus [11]
Thomson<span> is the scientist who designed an experiment that enabled the first successful detection of an individual subatomic particle. </span>J.J. Thomson<span> (Sir </span>Joseph John Thomson<span>, 1856-1940), who demonstrated in 1897 that "cathode rays" consisted of negatively-charged particles, later named electrons.</span>
6 0
3 years ago
Matt did an experiment to study the solubility of two substances. He poured 100 mL of water at 20 °C into each of two beakers la
Black_prince [1.1K]

Part 1 : Answer is only B substance is soluble in water.

In this experiment undissolved mass of each substance was measured. According to the given data, undissolved mass of substance B at 20 °C is 10 g while A is 50 g. Since, the initial added mass of each substance is 50 g, we can see that substance A is not soluble in water since the undissolved mass is 50 g.

Part 2 : Substance A is not soluble in water and substance B is soluble in water.

According to the given data, the undissolved mass of substance A remains as same as initial added mass, 50 g throughout the temperature range from 20 ° to 80 °C. Hence, we can conclude that substance A is not soluble in water.

But, according to the data, undissolved mass of substance B at 20 °C is 10 g. That means, 40 g of substance B was dissolved in water. When the temperature increases the undissolved mass of substance B decreases. Hence, we can conclude that substance B is soluble in water and solubility increases with temperature.


4 0
3 years ago
Read 2 more answers
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