The acid dissociation constant is 1.3 × 10^-3.
<h3>What is acid-dissociation constant?</h3>
The acid-dissociation constant is a constant that shows the extent of dissociation of an acid in solution. We have to set up the reaction equation as shown below;
Let the acid be HA;
HA + H2O ⇄ H3O^+ + A^-
since the pH of the solution is 2.57 then;
[H3O^+] = Antilog(-pH) = Antilog(-2.57) = 2.7 × 10^-3
We can see that; [H3O^+] = [A^-] so;
Ka = (2.7 × 10^-3)^2/(5.5 × 10^–3)
Ka = 1.3 × 10^-3
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Answer:The correct answer option A.
Explanation:

Q= heat removed from the water
m= mass of the water = 80 grams
c = heat capacity of water= 4.18 J/g°C

Q = -10,032 joules
-10,000 Joules
Negative sign indicates that heat was removed from the water.
Heat removed from the water of 80 gram of water is 10,032 Joules.Hence, the correct answer option A.
Explanation:
This process ensures that the pressure inside of the graduated cylinder is the same as the atmospheric pressure in the room.
Suppose the level of water inside and outside the cylinder is same, pressure stays the same. Therefore, total pressure of the is made equal to atmospheric pressure by adjusting the height of cylinder. it is done till the water level is equal.
According to the research, domain is the taxonomic classification level that is the largest or most broad.
<h3>What is domain?</h3>
It is the broadest taxonomic category in which known living things are classified.
In other words, it is the broadest category in which the different kingdoms of life can be organized, according to the classification models that are most widely accepted in the scientific community.
Therefore, we can conclude that according to the research, domain is the taxonomic classification level that is the largest or most broad.
Learn more about taxonomic classification here: brainly.com/question/13049455
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Answer:
pH = 10.9
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to say that the undergoing reaction between this buffer and OH⁻ promotes the formation of more CO₃²⁻ because it acts as the base, we can do the following:

The resulting concentrations are:
![[CO_3^{2-}]=\frac{0.1435mol}{0.25L}=0.574M \\](https://tex.z-dn.net/?f=%5BCO_3%5E%7B2-%7D%5D%3D%5Cfrac%7B0.1435mol%7D%7B0.25L%7D%3D0.574M%20%5C%5C)
![[HCO_3^{-}]=\frac{0.0265mol}{0.25L}=0.106M](https://tex.z-dn.net/?f=%5BHCO_3%5E%7B-%7D%5D%3D%5Cfrac%7B0.0265mol%7D%7B0.25L%7D%3D0.106M)
Thus, since the pKa of this buffer system is 10.2, the change in the pH would be:

Which makes sense since basic OH⁻ ions were added.
Regards!