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1 year ago

7

How are the properties of high-tech ceramics the same as those of traditional clay ceramics, and how are they different? Refer t

o specific substances in your answer.

1 answer:

algol131 year ago

3 0

Modern ceramics have all properties which have traditional ceramics for example hardness, high resistance to chemicals, and heat and they are different from traditional ceramic because have superior magnetic are or electrical properties.

One example is classical ceramic which is an insulator but when is dopped with ZnO it becomes a good conductor at high voltages.

to know more about clay ceramics and high tech ceramics here

brainly.com/question/17192744?referrer=searchResults

#SPJ4

You might be interested in

Compare the three atom diagrams. which one shows the electron with the highest potential energy

lara31 [8.8K]

Answer : The one diagram which shows the electron with the highest potential energy is attached below.

Explanation : One can easily find the highest potential energy of the atom just by looking at the diagram, the electron which is from farthest distance from the atomic nucleus will have the highest potential energy in the electron.

5 0

2 years ago

Example of oxidizing agents include

Ivahew [28]

Explanation:

Substances generally tends to specialize as either oxidizing or reducing agents.

An oxidizing agent is an electron acceptor which causes a co-reactant to be oxidized in a reaction.

Examples are:

Non-metals especially oxygen and the halogens.

Other examples are H₂SO₄ , HNO₃, KMnO₄, K₂Cr₂O₇

learn more:

Oxidizing and reducing agents brainly.com/question/5558762''

#learnwithBrainly

4 0

3 years ago

At sea level, where the pressure was 104 kPa and temperature 21.1 ºC, a certain mass of air occupies 2.0 m3 . To what volume wil

Romashka [77]

Answer:

The volume of air at where the pressure and temperature are 52 kPa, -5.0 ºC is $3.64 m^3$ .

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 104 kPa

$P_2$ = final pressure of gas = 52 kPa

$V_1$ = initial volume of gas = $2.0m^3$

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $21.1^oC=273+21.1=294.1K$

$T_2$ = final temperature of gas = $-5.0^oC=273+(-5.0)=268 K$

Now put all the given values in the above equation, we get:

$\frac{104 kPa\times 2.0m^3}{294.1 K}=\frac{52 kPa\times V_2}{268 K}$

$V_2=3.64 m^3$

The volume of air at where the pressure and temperature are 52 kPa, -5.0 ºC is $3.64 m^3$ .

3 0

2 years ago

If faucet drips 5 mL of water each minute, what is the volume of water dripped at the end of five minutes?

kiruha [24]

If the faucet drops at 5 mL per minute you just have to do the following steps to find out.

5 mL for the dripping rate times 5 for the minutes.

The answer would result being 25mL

Hope this helps! Stay safe!

6 0

2 years ago

Read 2 more answers

Lead(II) nitrate is added slowly to a solution that is 0.0800 M in Cl− ions. Calculate the concentration of Pb2+ ions (in mol /

barxatty [35]

Answer:

$[Pb^{2+}]=3.9 \times 10^{-2}M$

this is the concentration required to initiate precipitation

Explanation:

$PbCl_2$ ⇄ $Pb^{2+}+2Cl^-$

Precipitation starts when ionic product is greater than solubility product.

Ip>Ksp

Precipitation starts only when solution is supersaturated because solution become supersaturated then it does not stay in this form and precipitation starts itself only solution become saturated.

This usually happens when two solutions containing separate sources of cation and anion are mixed together and here also we are mixing lead (||)nitrate solution(source of lead(||)) into the Cl- solution.

$Ip=[Pb^{2}][2Cl^-]^2=Ksp$

$Ksp=2.4\times 10^{-4}$

lets solubility=S

$[Pb^{2+}] = S$

$[Cl^-]=2S$

$Ksp=[Pb^{2+}]\times [Cl^-]^2$

$Ksp=S \times (2S)^2$

$Ksp=4S^3$

$S=\sqrt[3]{\frac{Ksp}{4} }$

$S=3.9\times 10^{-2}$

$[Pb^{2+}]=3.9 \times 10^{-2}M$ this is the concentration required to initiate precipitation

4 0

2 years ago