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Gelneren [198K]
3 years ago
6

A certain alkyl halide forms a carbocation that is more stable than the carbocation formed from isopropyl bromide. What is the m

ost likely chemical name of the unknown?
Chemistry
1 answer:
pashok25 [27]3 years ago
3 0

Answer:

t-butyl bromide

Explanation:

As a general rule, carbocation stability depends on the number of substituents attached to central carbon. In isopropyl bromide, the carbocation formed is secondary carbocation, as Br group is the most likely to leave from isopropyl chain. The more stable carbocation would be one stablized by 3 carbon, or tertiary carbocation. The simplest of these would be t-butyl bromide which is carbon attached with 3 methyl groups

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How many grams of H 2O are produced from 28.8 g of O 2? (Molar Mass of H 2O = 18.02 g) (Molar Mass of O 2=32.00 g) 4 NH 3 (g) +
krek1111 [17]

Answer:  13.9 g of H_2O will be produced from the given mass of oxygen

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} O_2=\frac{28.8g}{32.00g/mol}=0.900moles

The balanced chemical reaction is:

4NIO_2(g)+7O_2(g)\rightarrow 4NO_2(g)+6H_2O(g)

According to stoichiometry :

7 moles of O_2 produce =  6 moles of H_2O

Thus 0.900 moles of O_2 will produce =\frac{6}{7}\times 0.900=0.771moles  of H_2O

Mass of H_2O=moles\times {\text {Molar mass}}=0.771moles\times 18.02g/mol=13.9g

Thus 13.9 g of H_2O will be produced from the given mass of oxygen

5 0
2 years ago
For a reaction 2A + B 2C, with the rate equation: Rate = k[A]2[B]
In-s [12.5K]
For reaction

2 A + B  ------------> 2 C  

Rate = K [ A ]² [ B ]

<span> the order with respect to A is 2 and the order overall is 3.
</span>
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3 0
3 years ago
2 H2(g) + O2(g) 2 H2000
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4 0
2 years ago
Most bones are connected at Joints by​
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7 0
3 years ago
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1 mol of any gas or mix of gases at STP conditions will have a volume of 22.4 L. Since the problem doesn’t said what are the conditions I will asume that are STP condition and the volume of one mole of the mix will have a volume of 22.4 L.

You may know that density is
D=m/v

In one mole of air I will have 80% of Nitrogen (N2) and 20% oxygen (O2).

So the mass of one mole of air will be

14 x2x0.80+16x2x0.20 = 22.4 g + 6.4 g = 28.8 g

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5 0
3 years ago
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