Answer:

Explanation:
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In this case, by knowing that the used NaOH equals in moles the acid (monoprotic) as shown below, during the titration:

By knowing the volume and the concentration of the NaOH, one obtains:

Thus, the molar mass of the acid is computed based on the previously computed moles and the given mass as follows:

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Answer:
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Answer:
Cu(NO3)2(aq)+Pb(s) ⇌ Pb(NO3)2(aq)+Cu(s)
Explanation:
If we look at the both reactions closely, we will quickly discover that the reaction CuSO4(aq)+Pb(s) ⇌ PbSO4(s)+Cu(s) involves PbSO4.
The compound PbSO4 is insoluble in water and sinks to the bottom of the reaction vessel. When this occurs, the concentration of Pb^2+ becomes low. This will bring about a low voltage in the cell.
On the other hand, Pb(NO3)2 is soluble in water hence the cell voltage in this case is higher than the former.