A Grignard reagent and a ketone are reacted in ether solution and, followed by an acid workup, form a tertiary alcohol. Recall t
hat Grignard reactions must be scrupulously dry in order to work effectively. A common method of drying glassware is to rinse with acetone prior to use.
1. Why is rinsing with acetone not suitable for the reaction stated in the question.
a) Magnesium does not dissolve in acetone.
b) Water dissolves in acetone. Adding acetone will add water to the reaction flask.
c) Magnesium dissolves in acetone. Adding acetone will remove a vital reactant from the flask.
d) Acetone is a ketone. Grignard reagents will react with acetone to make an unwanted byproduct.
1. Why is rinsing with acetone not suitable for the reaction stated in the question.
a) Magnesium does not dissolve in acetone.
b) Water dissolves in acetone. Adding acetone will add water to the reaction flask.
c) Magnesium dissolves in acetone. Adding acetone will remove a vital reactant from the flask.
d) Acetone is a ketone. Grignard reagents will react with acetone to make an unwanted byproduct.
1 answer:
Answer:
Option-D (Acetone is a ketone. Grignard reagents will react with acetone to make an unwanted byproduct.) is the correct answer.
Explanation:
Grignard reagents are formed by reacting alkyl halides in the presence of ether and dry atmosphere at controlled conditions. The rinsing of glassware is not suitable to be done with Acetone. This is because of the reactivity of Grignard reagents towards the carbonyl compounds.
In the scheme below it is assumed that a grignard reagent (ethyl magnesium bromide) was reacted with pentan-2-one to synthesise a tertiary alcohol (3-methylhexan-3-ol). But when the glassware is rinsed with acetone, some acetone left in glassware (like Round bottom flask) will react with the grignard reagent and will produce corresponding tertiary alcohol (2-methylbutan-2-ol in this assumption).
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Answer:
Explanation:
The Ideal Gas equation is:
(1)
Where:
is the pressure of the gas
the number of moles of gas
is the gas constant
is the absolute temperature of the gas in Kelvin.
is the volume
It is important to note that the behavior of a real gas is far from that of an ideal gas, taking into account that <u>an ideal gas is a single hypothetical gas</u>. However, under specific conditions of standard temperature and pressure (T=0\°C=273.15 K and P=1 atm=101,3 kPa) one mole of real gas (especially in noble gases such as Argon) will behave like an ideal gas and the constant R will be .
However, in this case we are not working with standard temperature and pressure, therefore, even if we are working with Argon, the value of R will be far from the constant of the ideal gases.
Having this clarified, let's isolate from (1):
(2)
Where:
is the absolute temperature of the gas in Kelvin.
(3)
Finally: