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3 years ago

IWILL MARK BRAINLEST PLS HELP ASAP

Mathematics

1 answer:

IgorLugansk [536]3 years ago

3 0

Answer:

BCD = ECD

Step-by-step explanation:

they would equal the same thing because it is still the same shape

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If the value of x=4, y=3 and z= -2 find the value of 2x+3z

Oksana_A [137]

Answer:

Step-by-step explanation:

To find value:

2x + 3z

Given values:

x = 4, y = 3 and z = -2

Solution:

2x + 3z

(Putting the values of x = 4 and z = -2)

= 2(4) + 3(-2)

= 8 - 6

= 2 (Ans)

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2 years ago

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The Pollard cafeteria buys all of its utensils at the beginning of the year. After 22 days of school there is 152,640 forks left

Alika [10]

where is the question,it is incomplete. complete the question for your answer.

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2 years ago

Sarawongs school is selling tickets to the anual talent show on the first day of ticket sales the school sold 1 adult ticket and

vaieri [72.5K]

Price of one adult ticket is $9 and price of one student ticket is also $9.

Step-by-step explanation:

Let,

Adult ticket = x

Student ticket = y

According to given statement;

x+2y=27 Eqn 1

2x+2y=36 Eqn 2

Subtracting Eqn 1 from Eqn 2;

$(2x+2y)-(x+2y)=36-27\\2x+2y-x-2y=9\\x=9$

Putting x=9 in Eqn 1;

$9+2y=27\\2y=27-9\\2y=18$

Dividing both sides by 2;

$\frac{2y}{2}=\frac{18}{2}\\y=9$

Price of one adult ticket is $9 and price of one student ticket is also $9.

Keywords: linear equations, subtraction

Learn more about linear equations at:

#LearnwithBrainly

4 0

2 years ago

Select the expression below that is equal to 5(11 - m).

Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

5*11=55

5*-m=-5m

Your welcome

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2 years ago

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The illuminance of a surface varies inversely with the square of its distance from the light source.If the illuminance of a surf

VashaNatasha [74]

Answer:

Distance between the surface and source of light will be increased by 6 meters.

Step-by-step explanation:

The illuminance of a surface varies inversely with the square of ts distance from the light source.

Let illuminance of the surface = x lumens per square meter

and distance from a light source = y meter.

Now x ∝ $\frac{1}{y^{2} }$

Or $x=\frac{k}{y^{2} }$ [k = proportionality constant]

Now we will find the value of k.

k = xy²

k = 120×(6)²

k = 4320

We have to calculate the distance of the source if illuminance of the surface is 30 lumens per square meter.

$30=\frac{4320}{y^{2}}$

y² = $\frac{4320}{30}$

y² = 144

y = √144 = 12 meters

So the source of the light will be shifted away from the surface = 12 - 6 = 6 meters.

6 0

2 years ago