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Triss [41]
3 years ago
8

Hello please help!! thank you<3

Mathematics
1 answer:
Sonbull [250]3 years ago
7 0

Answer:

112

Step-by-step explanation:

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Solve for y<br><br> 13 = 6 + y
Leni [432]

Answer:

Step-by-step explanation:

6 + y = 13

y = 7

4 0
3 years ago
Read 2 more answers
Question 4 options:<br><br> tan Z<br><br><br> cos X<br><br><br> sin X<br><br><br> sin Z
ser-zykov [4K]

Answer:

sin X

Step-by-step explanation:

sin X = \frac{opposite}{hypotenuse} = \frac{YZ}{XZ} = \frac{84}{85}

4 0
3 years ago
Is -9, -4, 1 and 6 arithmetic
ra1l [238]

Answer:

Yes. It is an arithmetic sequence.

Step-by-step explanation:

The sequence would be add 5 every time.

-9 + 5 = -4

-4 + 5 = 1

1 + 5 = 6

8 0
3 years ago
Please answer immediately!!!!!!!!
Westkost [7]

Answer:

For tree see picture but instead of BG replace all values with RRBBB and see the notes above how to roate the colours instead of the shape roation below just do transition (0,0)(1,0) (1,1).

Then 13 colours minimum change.

This will be 3 + 5 + 4 each colour change = 12 each colour change. instead of doing the 56 each colour rotation below.

Step-by-step explanation:

make 4 bits of paper and label each side -1 and 1 and central 0

above central point vertically label 1 and -1 for transition.

Then change just top one 4x = 4 more

Do the same with 2nd from top = 8 more to include top changing 4x again.

Do the same with 2nd from bottom = 12 more

Do the same with bottom = 16 more.

4+8+12+16 =40

Then repeat the process on side for blocks and we can double up

40+40 = 80.

When drawing tree clearly state columns

Top two are red only change

Top of tree will read in order so where ever you see capital R you will know its a new column for the tree and fill in when you understand the 254 transitions of a 5 column tree. Then change B + R accordingly when you get to row 6. Here you just start changing blue back to the top after row 5

Columns go down and rows go across its a new row you will need

approx 5-6 rows each colour change.

For the ones started for you below its just transition and colour stays where it is.  

R x    RT 45d   RT (1,0) 45   RT (1,1) 45  RT (1,0)

R x    R x

B x    B x

B x    B x

B x    B x

'x' = RED Normal as you keep 0 zero central on all 4 bricks and work with top row as explained below.

Top RED  brick you have to Right side place transition on every 2nd column for each colour and thenyou should find a pattern if youve numbered your papers or brcks to just see how it works. (hanging out one side call this 'off set' or call it T for transition (1.0)

RED Central 'diagonal' call it  '45 degree rotate'

E ABCD RED Normal edge transition its edge so it hangs out

E ABCD RED On edge 45 degree diagonal its edge so it hangs out

2nd only change

S ABCD 1st red normal 2nd red Right side place rotate

S ABCD 1st red right side rotate 2nd red 45 degree rotate

S ABCD 1st red right side rotate 2nd central place 45 degree rotate  

S ABCD 1st red right side rotate 2nd edge Normal edge transition

S ABCD 1st red right side rotate 2nd 45 degree its edge diagonal

2nd is repeated by changing 1st 4x more in bold. see what is now missing for 1st red. and copy the 2nd changes to 1st all whilst rotaing 2nd again in change .

Copy paste the work

Then apply this to 3 + 4 + 5th brick.

As the above shows 10 and when you finish 2nd and 1st it will be 14 total

Then 3 will be 14 again

and 4th brick will be 14 again

and 5th brick will be 14 again

making the transitions and rotations where all bricks in same level placement

14 x 4 = 56 transitions/rotations

Then repeat again for 1 blue at the top change

Then repeat again for 2 blue at the top for change

Then repeat again for 2 blue in the top middle

Then repeat again for 2 blue in the bottom middle

You can label tree

RR = Red rotation

BR = Blue rotation

RRE= Red rotation edge

BRE = Blue rotation

and colour code blue and red pens.

You can label transitions

RT = red transition (1,0)

RT = red transition (1,1) for central

and same for blue etc..

The end result will be 56 x 4 = 224 diagram tree

On ce you learn this it will take just 6 minutes to write out.

6 0
3 years ago
We considered the differences between the temperature readings in January 1 of 1968 and 2008 at 51 locations in the continental
mr Goodwill [35]

Answer:

1.1-2.02\frac{4.9}{\sqrt{50}}=-0.30    

1.1+2.02\frac{4.9}{\sqrt{50}}=2.50    

So on this case the 90% confidence interval would be given by (-0.30;2.50)  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=1.1 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=4.9 represent the sample standard deviation

n=51 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=51-1=50

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,50)".And we see that t_{\alpha/2}=2.02

Now we have everything in order to replace into formula (1):

1.1-2.02\frac{4.9}{\sqrt{50}}=-0.30    

1.1+2.02\frac{4.9}{\sqrt{50}}=2.50    

So on this case the 90% confidence interval would be given by (-0.30;2.50)    

8 0
3 years ago
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