All categories

3 years ago

I need help please.

Mathematics

1 answer:

patriot [66]3 years ago

4 0

Answer:

b 4

Step-by-step explanation:

You might be interested in

Heyy! i’ll give brainliest please help.

Murrr4er [49]

Answer:

thought i had it but answer is B......

6 0

3 years ago

TIME REMAINING

Leya [2.2K]

Answer:

w=-7/2z

Step-by-step explanation:

to solve for w you firstly have to group the like terms

5w-3w=2z-9z

2w=-7z

then you have to divide both sides by 2 inorder to remain with w on one side.

2w/2=-7/2

w=-7/2

I hope this helps

3 0

3 years ago

Read 2 more answers

An object has a mass of 12kg. On planet A the object weighs 69N. The force of gravity on planet a is:

astraxan [27]

w = mg

w/m = g

69N / 12kg = 5.75 N/kg

<u>Answer: B) 5.75 m/s2</u>

8 0

3 years ago

F(x) = 2x is translated 4 units up

kolbaska11 [484]

f(x) = 2x

f(x) = 2x + 4 (Is translated 4 units up.)

6 0

3 years ago

At the beginning of each of her four years in college, Miranda took out a new Stafford loan. Each loan had a principal of $5,500

kaheart [24]

Answer:

D. $31,337.27

Step-by-step explanation:

We have that the initial amount of the loan is $5500.

Miranda took the loan for 4 years. So, the total present value is $5500×4 = $22,000.

The rate of interest on the loan is 7.5% i.e. 0.075 and it was for the duration of 10 years.

Also, it is given that the loan was compounded annually.

We have the formula as,

$P=\frac{\frac{r}{n}\times PV}{1-(1+\frac{r}{n})^{-t\times n}}$

i.e. $PV=\frac{P\times [1-(1+\frac{r}{n})^{-t\times n}]}{\frac{r}{n}}$

Substituting the values, we get,

i.e. $PV=\frac{P\times [1-(1+\frac{0.075}{12})^{-10\times 12}]}{\frac{0.075}{12}}$

i.e. $22000=\frac{P\times [1-(1+0.00625)^{-120}]}{0.00625}$

i.e. $22000=\frac{P\times [1-(1.00625)^{-120}]}{0.00625}$

i.e. $22000=\frac{P\times [1-0.4735]}{0.00625}$

i.e. $22000=\frac{P\times 0.5265}{0.00625}$

i.e. $P=\frac{22000\times 0.00625}{0.5265}$

i.e. $P=\frac{137.5}{0.5265}$

i.e. $P=261.16$

Thus, the total lifetime cost to pay of the loans compounded annually = 261.16 × 120 = $31,339.2

Hence, the total cost close to the answer is $31,337.27

7 0

3 years ago

Read 2 more answers