Answer: 10
----------------------------------------------
Explanation:
Segment TU must be congruent (equal in length) to segment UV in order for the angle TSV to be bisected by segment SU
Bisected = cut in half
So because TU = UV, we can say,
TU = UV
3x+18 = 4x+8
3x+18-3x = 4x+8-3x
18 = x+8
18-8 = x+8-8
x = 10
Answer: The total number of logs in the pile is 6.
Step-by-step explanation: Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two logs.
We are to find the total number of logs in the pile.
Let n represents the total number of logs in the pile.
Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with
first term, a = 32 and common difference, d = -6.
We know that
the n-th term of an arithmetic sequence with first term a and common difference d is

Since there are n logs in the pile, so we get

Thus, the total number of logs in the pile is 6.
All real numbers is the answer
You did not provide a list of expressions to select from.
Let A = area
Let w = width
Let (w + 5) = length
A = (w + 5)w