P(7,6), Q(1,6), R(4,2)
We have PQ parallel to the x axis. We'll call that the base,
b = 7 - 1 = 6
The altitude is then the y difference h = 6 - 2 = 4
The area is 
Answer: 12 square units
In general we can use the shoelace formula for the area of any polygon given coordinates. We write the points like this:
(7,6), (1,6), (4,2)
(1,6), (4,2), (7,6)
The area is then half the absolute value of the sum of the cross products:

It's the first one, an algebraic expression contains variables
To find if a series is either geometric or arithmetic:
it must satisfy this property:
Arithmetic:
a(n+1) - a(n) = const
Geometric:
a(n+1)/a(n) = const
In your case:
r1 = 7 -4 = 3
r2 = 12 - 7 = 5
r1 != r2 (not arirthmetic)
Geometric check:
r1 = 7/4
r2 = 12/7
r1 != r2 (not Geometric)
so neither.
Answer:
-15X^3y^2Z^2 is the answer
.58. Absolute value gets rid of negative.