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Kisachek [45]
4 years ago
15

Is 6- 53 positive or negative

Mathematics
2 answers:
NARA [144]4 years ago
7 0
6 - 53 is Negative, I think.
Anuta_ua [19.1K]4 years ago
4 0
I t ' s n e g a t i v e .
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Tell which property is represented. 9 x (5 x 2) = (9 x 5) x 2
Tcecarenko [31]

Answer:

Step-by-step explanation:

associative property because the numbers are changing in postition throughout the equation.  

5 0
4 years ago
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F(n)=4n <br> g(n)=n2+2n <br> find f(g(-6))
ELEN [110]

Answer:

When f(n) = 4n and g(n) = n² + 2n, f(g(-6)) = 96.

Step-by-step explanation:

To evaluate f(g(-6)), first find g(-6).

g(n) = n² + 2n

Substitute value.

g(-6) = (-6)² + 2(-6)

Square -6. Remember that (-x)² = x²

g(-6) = 36 + 2(-6)

Multiply 2 and -6.

g(-6) = 36 - 12

Subtract 12 from 36.

g(-6) = 24.

Now knowing this, substitute that value into f(n).

f(g(-6)) = f(24)

f(n) = 4n

Substitute value.

f(24) = 4(24)

Multiply 4 and 24.

f(24) = 96.

8 0
3 years ago
For what values of X are the statements below true
Galina-37 [17]

Answer:

See solutions below

Step-by-step explanation:

For what values of X are the statements below true

A. 1x>x+1

x >x+1

x-x>1

0x > 1

x > 1/0

X >∞

B) |1-x|>3

The fucntion can both be positive and negative

For the negative function

-(1-x) > 3

-1+x > 3

x > 3+1

x > 4

For the positive function

1-x > 3

-x > 3 - 1

-x > 2

x < -2

Hence the required solutions are x > 4 and x < -2

c) For the equation

|x-15| < 0

-(x - 15) < 0

-x + 15 < 0

-x < -15

x > 15

Also x-15 < 0

x < 0+15

x < 15

Hence the required solution is x > 15 and x < 15

3 0
3 years ago
The two solids are similar and the ratio between the lengths of their edges is 2:9 what is the ratio of their surface areas
aliina [53]
I THINK the ratio is 4:81 but i don’t know lol
3 0
3 years ago
Read 2 more answers
An employer has a staff of eighty actuaries, ten of whom are student actuaries. A student actuary is allowed a total of ten week
sergiy2304 [10]

Answer:

0.1111

Step-by-step explanation:

From the given information;

Number of staffs in the actuary = 80

Out of the 80, 10 are students.

i.e.

P(student actuary) = 10/80 = 0.125

number of weeks in a year = 52

off time per year = 10/52 = 0.1923

P(at work || student actuary) = (50 -10/52)

= 42/52

= 0.8077

P(non student actuary) = (80 -10)/80

= 70 / 80

= 0.875

For a non-student, they are only eligible to 4 weeks off in a year

i.e.

P(at work | non student) = (52-4)/52

= 48/52

= 0.9231

∴

P(at work) = P(student actuary) × P(at work || student actuary) + P(non student actuary) × P(at work || non studnet actuary)

P(at work) =  (0.125 × 0.8077) + ( 0.875 × 0.9231)

P(at work) = 0.1009625 + 0.8077125

P(at work) = 0.90868

Finally, the P(he is a student) = (P(student actuary) × P(at work || student actuary) ) ÷ P(at work)

P(he is a student) = (0.125 × 0.8077) ÷ 0.90868

P(he is a student) = 0.1009625 ÷ 0.90868

P(he is a student) = 0.1111

5 0
3 years ago
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