The possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are 
<h3>How to determine the possible zeros?</h3>
The function is given as:
f(x) = 3x^6 + 4x^3 -2x^2 + 4
The leading coefficient of the function is:
p = 3
The constant term is
q = 4
Take the factors of the above terms
p = 1 and 3
q = 1, 2 and 4
The possible zeros are then calculated as:

So, we have:

Expand

Solve

Hence, the possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are 
Read more about rational root theorem at:
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The answer is 3, 3x5=16 3x9=27 only 3 can divide 27 :)
Ask yourself f(x) equals X +18 to the second power +12
Answer:
Answer B
Step-by-step explanation:
therw is one full one and one with five
Answer:
APBCD
Step-by-step explanation:
Because this make sance