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tekilochka [14]
3 years ago
13

What is the lateral surface area of the square pyramid represented by this net?

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
4 0

Answer:

340 ft²

Step-by-step explanation:

From the diagram, we can see that the shape is made up of a square and 4 triangles. (We know it's a square as its width equals its length).

First, find the area of the square.

Area of a square = width x length = 10 x 10 = 100 ft²

All the triangles are the same, so we need to find the area of one of the triangles and multiply it by 4.

Area of a triangle = 1/2 x base x height = 1/2 x 10 x 12 = 60 ft²

So the total area of all 4 triangles = 4 x 60 = 240 ft²

Therefore the total surface area = 100 + 240 = 340 ft²

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Virty [35]
The area of a parallelogram is the product of the length of the base and the height measured perpendicular to the base.

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Which are the center and radius of the circle with equation (x + 5)2 + (y - 4)2 = 9?
alina1380 [7]

Answer:

Center (-5,4) radius 3

Step-by-step explanation:

The standard equation of a circle is

(x-h)^2+(y-k)^2=r^2

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4 0
3 years ago
(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll
goldenfox [79]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

In point 1:

The Reflexive closure:  

Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is  (0,0),(1,1),(2,2) \ and \ (3,3)

Thus, the reflexive closure: R={(0,0),(0,1),(1,1),(1,2),(2,0),(2,2),(3,0), (3,3)}

In point 2:

The Symmetric closure:

R relation symmetrically closes by adding(b,a) to R for each (a,b) of R  Therefore, here (b,a) is:   (0,1),(0,2)\ and \ (0,3)

Thus, the Symmetrical closure:

R={(0,1),(0,2),(0,3)(1,0),(1,1)(1,2),(2,0),(2,2),(3,0), (3,3)}

8 0
3 years ago
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