1/4
and 6/4 there we go here is your answer
The given answer should be "3/2", its because "32" is not possible in anyway..
tan C = sin C / cos C
Where sin C = 3 / 3.61
And
cos C = 2 / 3.61
Now
tan C = (3 / 3.61) / (2 / 3.61) = (3 / 3.61) x (3.61 /
2) = 3 / 2
<span>Thus tan C is the correct choice. </span>
Answer:
93
Step-by-step explanation:
Answer:
Water needed for pool = 486 cubic feet
Plastic liner required for the pool = 298.3 feet
Step-by-step explanation:
Top view of the pool is a composite figure, having one rectangle and a trapezoid.
1). Water needed for the pool = volume of the pool
Volume of the pool = Area of the base × Depth
= (Area of the rectangle + Area of the trapezoid)× depth
Area of the trapezoid = ![\frac{1}{2}(b_{1}+b_{2})\times h](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28b_%7B1%7D%2Bb_%7B2%7D%29%5Ctimes%20h)
= ![\frac{1}{2}(11+9)\times (12-1.5)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2811%2B9%29%5Ctimes%20%2812-1.5%29)
= 105 ft²
Area of the rectangle = Length × width
= 11 × 1.5
= 16.5 ft²
Now, volume of the pool = (105 + 16.5) × 4
= 121.5 × 4
= 486 cubic feet
b). Liner required = surface area of the pool excluding top
= Surface area of the walls + Area of the pool base
= (Perimeter of the pool) × depth + area of the base
= (12 + 11 + 1.5 + 10.7 + 9)×4 + 121.5
= 176.8 + 121.5
= 298.3 square feet
Therefore, amount of water required = 486 cubic feet
liner needed = 298.3 square feet
Answer:
323.75 km
Step-by-step explanation:
185/100 = 1.85 km per nm
1.85 * 175 = 323.75 km