As per Newton's II law we know that
here F = force applied
m = mass of object = 2 kg
a = acceleration = 2 m/s^2
now as per above formula we will have
so here applied force on the ball will be 4 N
Read the paragraph and then answer the question. "A giraffe has to stretch its neck to reach leaves for food. Over time, the gir
2 answers:
You might be interested in
Answer:
<em>1.228 x </em><em> mm </em>
<em></em>
Explanation:
diameter of aluminium bar D = 40 mm
radius of aluminium bar R = D/2 = 40/2 = 20 mm
diameter of hole d = 30 mm
radius of the hole r = d/2 = 30/2 = 15 mm
compressive Load F = 180 kN = 180 x N
modulus of elasticity E = 85 GN/m^2 = 85 x Pa
length of bar L = 600 mm
length of hole = 100 mm
true length of bar = 600 - 100 = 500 mm
area of the bar A = = 3.142 x
= 1256.8 mm^2
area of hole a = =
= 549.85 mm^2
Total contraction of the bar =
total contraction =
==> = <em>1.228 x </em>
<em> mm </em>