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4 years ago

Which is a compound? Select one: a. O2 b. Cl2 c. Kr d. CuF2

Physics

2 answers:

lyudmila [28]4 years ago

4 0

CuF2 is the Answer if it’s wrong let me know

mixer [17]4 years ago

4 0

No u are right! its CuF2 Hope it helps

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Which image represents two equal displacements?

sesenic [268]

Answer:

It is C on Edge 2020.

6 0

3 years ago

A student forgets to turn off a 6.00x 10² W block heater of a car when the weather turns warm. If 14 h goes by before he shuts i

Inga [223]

Answer: 8.4 kW•hr

Explanation:

600 W • (14 hr) / (1000 W/kW) = 8.4 kW•hr

3 0

3 years ago

A 275-g sample of nickel at 100.0°C is placed in 100.0 mL of water at 22.0°C. What is the final temperature of the water? Assume

Mademuasel [1]

Answer:

39.6138 °C

Explanation:

Heat gain by water = Heat lost by nickel

Thus,

$m_{water}\times C_{water}\times (T_f-T_i)=-m_{nickel}\times C_{nickel}\times (T_f-T_i)$

Where, negative sign signifies heat loss

Or,

$m_{water}\times C_{water}\times (T_f-T_i)=m_{nickel}\times C_{nickel}\times (T_i-T_f)$

For water:

Volume = 100.0 mL

Density of water= 1 g/mL

So, mass of the water:

$Mass\ of\ water=Density \times {Volume\ of\ water}$

$Mass\ of\ water=1 g/mL \times {100.0\ mL}$

Mass of water = 100 g

Initial temperature = 22.0 °C

Specific heat of water = 4.186 J/g°C

For nickel:

Mass = 275 g

Initial temperature = 100 °C

Specific heat of nickel = 0.444 J/gK = 0.444 J/g°C

So,

$100\times 4.186\times (T_f-22.0)=275\times 0.444\times (100-T_f)$

$418.6\times (T_f-22.0)=122.1\times (100-T_f)$

$418.6\times T_f+122.1\times T_f=21419.2$

$T_f=39.6138\ ^{0}C$

Thus,

The final temperature of the combined metals is 39.6138 °C

4 0

3 years ago

Read 2 more answers

Warm air and water rise because...

Igoryamba

We know that an object floats in a fluid if the density of the object is less than the density of the fluid. When some air or water is heated, it expands. That makes its density less than cooler air or water, so it floats in them.

3 0

3 years ago

Read 2 more answers

A 10-kg disk-shaped flywheel of radius 9.0 cm rotates with a rotational speed of 320 rad/s. Part A Determine the rotational mome

Leya [2.2K]

Answer:

(A). The rotational momentum of the flywheel is 12.96 kg m²/s.

(B). The rotational speed of sphere is 400 rad/s.

Explanation:

Given that,

Mass of disk = 10 kg

Radius = 9.0 cm

Rotational speed = 320 m/s

(A). We need to calculate the rotational momentum of the flywheel.

Using formula of momentum

$L=I\omega$

$L=\dfrac{1}{2}mr^2\omega$

Put the value into the formula

$L=\dfrac{1}{2}\times10\times(9.0\times10^{-2})^2\times320$

$L=12.96\ kg m^2/s$

(B). Rotation momentum of sphere is same rotational momentum of the flywheel

We need to calculate the magnitude of the rotational speed of sphere

Using formula of rotational momentum

$L_{sphere}=L_{flywheel}$

$I\omega_{sphere}=I\omega_{flywheel}$

$\omega_{sphere}=\dfrac{I\omega_{flywheel}}{I_{sphere}}$

$\omega_{sphere}=\dfrac{I\omega_{flywheel}}{\dfrac{2}{5}mr^2}$

Put the value into the formula

$\omega_{sphere}=\dfrac{12.96}{\dfrac{2}{5}\times10\times(9.0\times10^{-2})^2}$

$\omega_{sphere}=400\ rad/s$

Hence, (A). The rotational momentum of the flywheel is 12.96 kg m²/s.

(B). The rotational speed of sphere is 400 rad/s.

4 0

3 years ago