The right answer is C. never
The quotient of two algebraic expressions is a<em> fractional expression.
</em> Moreover, the quotient of two <em>polynomials</em> such as:
is called a rational expression. So according to this definition rational expressions does not contain logarithmic functions. In fact, a rational expression is an expression that is the ratio of two polynomials like this:
Answer:
Step-by-step explanation:
It’s C
Answer:
h(8q²-2q) = 56q² -10q
k(2q²+3q) = 16q² +31q
Step-by-step explanation:
1. Replace x in the function definition with the function's argument, then simplify.
h(x) = 7x +4q
h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q
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2. Same as the first problem.
k(x) = 8x +7q
k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q
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Comment on the problem
In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...
h(8q² -2q) = 56q² -14q +4z
and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.
In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.
They both saw the same amount because 6+3 = 9 and 3+6 = 9
The absolute value of x is simply x and followed by the expression.
X + 1 + x + 1 <_ 2
2x + 2 <_ 2
2x <_ 0
X <_ 0
Basically all values that follow this inequality will most likely hold true.
For instance. -1.
-1 + 1 = 0
Absolute value of -2 = 2.
2 is equal to 2. This expression holds true.
