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3 years ago

How do I simplify the expression 8x+2x-3y-9x

Mathematics

2 answers:

zloy xaker [14]3 years ago

8 0

X-3y because 8x+2x-9x is x

Schach [20]3 years ago

5 0

It's like adding and subtracting. All the ones with x's go together, and all the y's go together (or whatever other letters there are.) 8x+2x=10x

10x-9x=1x

1x=x (if there's a letter and the number next to it is 1 it is just the letter)

Now x-3y is your solution because x and y don't go together

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Hi, I'm often really slow at learning math and my condition makes it harder, can someone help me?

NARA [144]

The answer: 0, 4/5 and 5

Explanation: first, we factor out 2x and get: 2x(5x^2-29x+20)=0

In order for this equation to be equal to zero, either 2x must equal to zero or (5x^2-29x+20) must equal to zero

Having said that, if:
2x = 0
X=0

If:
(5x^2-29x+20) = 0
X=4/6, x=5

7 0

3 years ago

What is the equation of a line passing through (-3,7) and having a slip of -1/5

MrRa [10]

Answer:

$\large\boxed{D.\ y=-\dfrac{1}{5}x+\dfrac{32}{5}}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

We have the slope m = -1/5. Substitute:

$y=-\dfrac{1}{5}x+b$

Put the coordinates of the given point (-3, 7) to the equation:

$7=-\dfrac{1}{5}(-3)+b$

$7=\dfrac{3}{5}+b$ <em>subtract 3/5 from both sides</em>

$6\dfrac{2}{5}=b\to b=\dfrac{6\cdot5+2}{5}=\dfrac{32}{5}$

3 0

3 years ago

Jabo is standing next to a building. Jabo is 6.25 feet tall, and cast a shadow that 14 feet long. If the building cast a shadow

stich3 [128]

Answer:

64.286ft

Step-by-step explanation:

6.25-->14

x-->144in=12ft im going to asume you meant 144ft or that would be a very small building

14/6.25=2.24ft shadow for 1 real foot

144/2.24=about 64.286ft

5 0

3 years ago

What is the value of x?

Mumz [18]

Answer:

68 Degrees

Step-by-step explanation:

A triangle is 180 degrees. So,

Add 75 + 37 = 112

Subtract 112 from 180 = 68

4 0

3 years ago

Read 2 more answers

Sarah claims that the thickness of the spearmint gum she produces is 7.5 one-hundredths of an inch. A quality control specialist

satela [25.4K]

Answer:

$t=\frac{7.55-7.5}{\frac{0.103}{\sqrt{10}}}=1.539$

$p_v =2*P(t_{(9)}>1.539)=0.158$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis.

Step-by-step explanation:

Data given and notation

Data: 7.65, 7.60, 7.65, 7.7, 7.55, 7.55, 7.4, 7.4, 7.5, 7.5

We can begin calculating the sample mean given by:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And the sample deviation given by:

$s=\sart{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And we got:

$\bar X=7.55$ represent the sample mean

$s=0.103$ represent the sample standard deviation

$n=10$ sample size

$\mu_o =7.5$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is equal to 7.5 or no, the system of hypothesis would be:

Null hypothesis: $\mu = 7.5$

Alternative hypothesis: $\mu \neq 7.5$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{7.55-7.5}{\frac{0.103}{\sqrt{10}}}=1.539$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=10-1=9$

Since is a two sided test the p value would be:

$p_v =2*P(t_{(9)}>1.539)=0.158$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis.

3 0

4 years ago