Uhh pls help I got 3 mins left

Sonja [21]

1/2* N= 1/3
⇒ N= (1/3)/ (1/2)
⇒ N= (1/3)* (2/1)
⇒ N= 2/3

The final answer is N= 2/3~

3 0

3 years ago

An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est

amid [387]

Answer:

(38.1,88.6)

Step-by-step explanation:

We are given the following in the question:

Sample mean, $\bar{x}$ = 38.3

Sample size, n = 695

Alpha, α = 0.05

Population standard deviation, σ = 3.6

95% Confidence interval:

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$38.3 \pm 1.96(\frac{3.6}{\sqrt{695}} ) = 38.3 \pm 0.267 = (38.033,38.567) \approx (38.1,88.6)$

8 0

3 years ago

One of the legs of a right triangle measures 9 cm and the other leg measures 11 cm.

ikadub [295]

Answer:

$\boxed {\boxed {\sf 14.2 \ cm}}$

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean Theorem to solve for the sides.

$a^2+b^2=c^2$

where <em>a</em> and<em> b</em> are the legs and <em>c</em> is the hypotenuse. In this triangle, we know the legs are 9 centimeters and 11 centimeters, or:

a= 9 cm
b= 11 cm

Substitute these values into the formula.

$(9 \ cm)^{2} +(11 \ cm)^{2} =c^{2}$

Solve the exponents.

(9 cm)²= 9 cm*9 cm=81 cm²

$81 \ cm^{2} +(11 \ cm)^{2} =c^{2}$

(11 cm)²= 11 cm*11 cm= 121 cm²

$81 \ cm^{2} +121 cm^{2} =c^{2}$

Add the values on the left side.

$202 \ cm^{2} =c^{2}$

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

$\sqrt {202 \ cm^{2} }=\sqrt{c^{2} }$

$\sqrt {202 \ cm^{2} }=c$

$14.2126704036 \ cm =c$

We are told to round to the nearest tenth.

14.2<u>1</u>26704036

The 1 in the hundredth place tells us to leave the 2 in the tenth place.

$14.2 \ cm= c$

The hypotenuse is equal to <u>14.2 centimeters.</u>

3 0

3 years ago

The graph of y = f(x − 3) is a _____ of the graph of y = f(x).

Phoenix [80]

<h2>Answer:</h2>

shift

<h2>Step-by-step explanation:</h2>

These are common types of transformations of functions. Many functions have graphs that are simple transformations of the parent graphs, that are the most basic functions. In this way, we can use vertical and horizontal shifts to sketch graphs of functions. These are rigid transformations because the basic shape of the graph is unchanged. Therefore $y=f(x-3)$ is a Horizontal Shift, so the graph of the function $y=f(x)$ has been shifted 3 units to the right.