3 [ (20-4) / 2 ]= 3 * 16/2= 3 x 8 =24
5,(9)=5 9/9= 54/9=6
6/8/4= 6/2=3
Answer:
Step-by-step explanation:
Let d represent number of dolls in 2nd basket.
We have been given that a day-care center has 2 baskets of dolls. One basket has 8 dolls, and the other basket has an unknown number of dolls in it. We are asked to represent this situation in an expression.
The number in both baskets would be equal to dolls in 1st basket plus dolls in 2nd basket.
We can represent this information in an expression as:
Therefore, our required expression would be , where d represents number of dolls in 2nd basket.
Answer:
<h2>84in²</h2>
Step-by-step explanation:
If the first one is 7 inches long, and 6 inches wide, and the second one is also 7 inches long, but is 6x2 inches wide, then what's the area?
6x2=12
So, Picture Frame 2 = 12 inches wide
Formula for finding area = LxW
L = 7
W = 12
7x12=84
So hence, your answer is 84in²
The area of the second frame is 84in²
Thanks!
Answer:
You can use the coordinates of a figure to find its dimensions by finding the distance between two points. To find the distance between two points with the same x-coordinates, subtract their y-coordinates. To find the distance between two points with the same y-coordinates, subtract their x-coordinates.
Step-by-step explanation:
The first solution is quadratic, so its derivative y' on the left side is linear. But the right side would be a polynomial of degree greater than 1, so this is not the correct choice.
The third solution has a similar issue. The derivative of √(x² + 1) will be another expression involving √(x² + 1) on the left side, yet on the right we have y² = x² + 1, so that the entire right side is a polynomial. But polynomials are free of rational powers, so this solution can't work.
This leaves us with the second choice. Recall that
1 + tan²(x) = sec²(x)
and the derivative of tangent,
(tan(x))' = sec²(x)
Also notice that the ODE contains 1 + y². Now, if y = tan(x³/3 + 2), then
y' = sec²(x³/3 + 2) • x²
and substituting y and y' into the ODE gives
sec²(x³/3 + 2) • x² = x² (1 + tan²(x³/3 + 2))
x² sec²(x³/3 + 2) = x² sec²(x³/3 + 2)
which is an identity.
So the solution is y = tan(x³/3 + 2).
