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Debora [2.8K]
3 years ago
12

The figure below is a rectangular box in which EFGH and ABCD are rectangles and BF is perpendicular to planes EFGH and ABCD. Use

the figure to complete parys a through e.

Mathematics
1 answer:
vladimir1956 [14]3 years ago
4 0

Answer:

Step-by-step explanation:

Given question is incomplete: Find the compete question in the attachment.

a). Skew lines neither the parallel lines nor they intersect each other.

Two pairs of skew lines are BF and EH, & CG and EF.

b). Since EFGH and ABCD are rectangular planes and BF and DH are perpendicular to them,so both will be the altitudes between the planes.

Therefore, BF and DH will pe parallel.

c). BD and DH are the diagonals of the planes parallel to each other.

Therefore, BD and DH will be parallel.

d). Since BD and plane EFG don't intersect each other, so the solution will be an empty set.

e). HG is perpendicular to DH. So,the planes BDH and FHG containing these lines will be perpendicular to each other.

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Answer:

BCG =65

Step-by-step explanation:

DCG + GCB = DCB

We know BCG = 31x+3 and GCD = 12x+2  and BCD = 91

Substituting these in

12x+2 + 31x+3 = 91

Combine like terms

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Subtract 5 from each side

43x+5-5 = 91-5

43x = 86

Divide by 43

43x/43= 86/43

x=2

BCG = 31x+3

        =31(2)+3

         =62+3

           =65

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