The figure below is a rectangular box in which EFGH and ABCD are rectangles and BF is perpendicular to planes EFGH and ABCD. Use
the figure to complete parys a through e.
1 answer:
Answer:
Step-by-step explanation:
Given question is incomplete: Find the compete question in the attachment.
a). Skew lines neither the parallel lines nor they intersect each other.
Two pairs of skew lines are BF and EH, & CG and EF.
b). Since EFGH and ABCD are rectangular planes and BF and DH are perpendicular to them,so both will be the altitudes between the planes.
Therefore, BF and DH will pe parallel.
c). BD and DH are the diagonals of the planes parallel to each other.
Therefore, BD and DH will be parallel.
d). Since BD and plane EFG don't intersect each other, so the solution will be an empty set.
e). HG is perpendicular to DH. So,the planes BDH and FHG containing these lines will be perpendicular to each other.
You might be interested in
Answer:
this is the equation of the tangent at point (-1,1/e)
Step-by-step explanation:
to find the tangent line we need to find the derivative of the function g(x).
- we know that
this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'
to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1
using the equation of line:
we'll find the equation of the tangent line.
here (x1,y1) =(-1,1/e), and m = 3/e
this is the equation of the tangent at point (-1,1/e)