Answer : 
(1) 
Use FOIL method to mulitply (3x – 5)(3x – 5)

(2) 
Use FOIL method to mulitply (3x - 5)(3x + 5)

(3) 
Use FOIL method to mulitply -(3x + 5)(3x + 5)

(4) 
Use FOIL method to mulitply -(3x + 5)(3x - 5)

So equation 2 is true
Answer:
![12-[20-2(6^2\div3\times2^2)]=88](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%3D88)
Step-by-step explanation:
So we have the expression:
![12-[20-2(6^2\div3\times2^2)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D)
Recall the order of operations or PEMDAS:
P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.
E: Within the parentheses, if exponents are present, do them before all other operations.
M/D: Multiplication and division next, whichever comes first.
A/S: Addition and subtraction next, whichever comes first.
(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)
Thus, we should do the operations inside the parentheses first. Therefore:
![12-[20-2(6^2\div3\times2^2)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D)
The parentheses is:

Square the 6 and the 4:

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

Therefore, the original equation is now:
![12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%5C%5C%3D12-%20%5B20-2%2848%29%5D)
Multiply with the brackets:
![=12-[20-96]](https://tex.z-dn.net/?f=%3D12-%5B20-96%5D)
Subtract with the brackets:
![=12-[-76]](https://tex.z-dn.net/?f=%3D12-%5B-76%5D)
Two negatives make a positive. Add:

Therefore:
![12-[20-2(6^2\div3\times2^2)]=88](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%3D88)
Hello!

x² + 5x + 6
Find two numbers that add up to 5 and multiply to 6. We get:
2, 3
Therefore:
(x + 2)(x + 3)
Answer:
The interval is [4,7]
Step-by-step explanation:
The rate of change is given by
f(x2) - f(x1)
-------------------
x2 -x1
We want the rate of change to be 56
f(x2) - f(x1)
------------------- = 56
x2 -x1
We also know that the x2 is 7 so f(x2) = 192
192 - f(x1)
------------------- = 56
7 -x1
192 - f(x1) = 56( 7 -x1)
192 - f(x1) = 392 -56x1
Now we need to pick points from the table and see where it is true
(6,96)
192 - 96 = 392 -56*6
96=56 False
( 5,28)
192 - 28 = 392 -56*5
164=112 False
(4,24)
192 - 24 = 392 -56*4
168=168 True
The interval is [4,7]