How to solve this question? Show steps pls :)

1.What is the slope of the line?

baherus [9]

Answer:

1. slope is 2

2. a is 5

3. b is 6

4. 0

Step-by-step explanation:

4 0

3 years ago

The Slope of a Line

Klio2033 [76]

Answer:

m = -3

Step-by-step explanation:

Slope Formula: $m = \frac{y2-y1}{x2-x1}$

Simply plug in our coordinates to find slope:

m = (11 - 2)/(5 - 8)

m = 9/-3

m = -3

5 0

3 years ago

You have been asked to find the inverse of f (x) = 3+Vx - 1. What would your

Paha777 [63]

Answer:

Add 1 to both sides of the equation.

Subtract 3 from both sides of the equation.

Step-by-step explanation:

The inverse of a function refers to that function that tends to undo another function.

If we intend to find the inverse of the function, f(x) = 3+ V2 - 1, we have to first add 1 to both sides of the equation and subsequently subtract 3 from both sides of the equation before taking the square root of both sides to obtain the inverse function.

Step-by-step explanation:

I hope this helps you :)

-KeairaDickson

8 0

3 years ago

In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

Marina86 [1]

Answer:

(a) 0.94

(b) 0.20

(c) 90.53%

Step-by-step explanation:

From a population (Bernoulli population), 90% of the bearings meet a thickness specification, let $p_1$ be the probability that a bearing meets the specification.

So, $p_1=0.9$

Sample size, $n_1=500$ , is large.

Let X represent the number of acceptable bearing.

Convert this to a normal distribution,

Mean: $\mu_1=n_1p_1=500\times0.9=450$

Variance: $\sigma_1^2=n_1p_1(1-p_1)=500\times0.9\times0.1=45$

$\Rightarrow \sigma_1 =\sqrt{45}=6.71$

(a) A shipment is acceptable if at least 440 of the 500 bearings meet the specification.

So, $X\geq 440.$

Here, 440 is included, so, by using the continuity correction, take x=439.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{339.5-450}{6.71}=-1.56$ .

So, the probability that a given shipment is acceptable is

$P(z\geq-1.56)=\int_{-1.56}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}}=0.94062$

Hence, the probability that a given shipment is acceptable is 0.94.

(b) We have the probability of acceptability of one shipment 0.94, which is same for each shipment, so here the number of shipments is a Binomial population.

Denote the probability od acceptance of a shipment by $p_2$ .