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ANTONII [103]
2 years ago
12

What is the projected amount of the sales are $25.9 billion and expect to increase by 20%

Mathematics
1 answer:
rewona [7]2 years ago
8 0
$31.08 billion
25.9 \times .20 + 25.9
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Find the slope of the line that passes through (8, 6) and (2, 7).
Amiraneli [1.4K]
Vas happenin!!

Slope form - y2-y1/x2-x1

7-6/ 2-8

1/-6

Your slope is -6x


Hope this helps

-Zayn Malik
6 0
2 years ago
Find the slopes of the asymptotes of the hyperbola with the following equation.
frosja888 [35]
You are given the equation 36 = 9x² + 4y². You are asked to find the slopes of the asymptotes of the hyperbola. A hyperbola has the following general equation x²/a² + y²/b² = 1. the goal here is to find the slopes of the hyperbolic equation. So divide both sides by 36

36 = 9x² + 4y²
(1/36)[36 = 9x² + 4y²]
1 = x²/4 + y²/9
a² = 4
a = 2
and
b² = 9
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To find the slope, divide a/b and you will get 2/3.
3 0
3 years ago
A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the
grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = \frac{diameter}{2}=\frac{66}{2} =33 \ mm

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = \frac{4}{3}\pi r^3

Now Volume of Gumball = \frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = \frac{diameter}{2}=\frac{58}{2} =29 \ mm

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = \frac{4}{3}\pi r^3

So Volume of gumball's spherical hollow core = \frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = 150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = 48347.6\ mm^3

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0
3 years ago
F(x)=4(x+2)(x+2)-6 in standard form
ollegr [7]

Answer:

4x^2 + 4x -2

Step-by-step explanation:

Use FOIL to solve (x+2) (x+2)

4(x^2 + 4x +4) - 6

4x^2 + 4x -2

8 0
3 years ago
10. A group of 10 people go to see a movie. The tickets
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6 adults were in the group and 4 children
3 0
3 years ago
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