Answer:
391.46 L
Explanation:
Given:
Initial temperature of the water = 23.4°C
Final temperature of the water = 39°C
Temperature change for the water, ΔT = (39 - 23.4) = 15.6°C
Heat absorbed by the water = 2.55 × 10⁴ kJ = 2.55 × 10⁷ J
Density of the water = 0.998 g/mL
Specific heat of the water, C = 4.184 J/g°C
Now,
The heat absorbed by the water, q = mCΔT
where, m is the mass of the water
Thus,
we have
2.55 × 10⁷ J = m × 4.184 × 15.6
or
m = 390682.45 grams
also,
Density = mass / volume
thus,
0.998 = 390682.45 / volume
or
Volume = 391465.38 mL
or
Volume = 391.46 L
Answer: The water by-product produced arises from the carboxy-terminus of one amino acid with the amine terminus of a second amino acid
Answer:
Butanoic Acid:
I have attached the structure of Butanoic Acid. Please refer to the attachment.
Explanation:
Solution:
First of all, we need to calculate the double bond equivalent (DBE) for the compound given:
Compound = C4H8O2
DBE = (C +1) - (H + X - N)/2
C = no. of carbons
H = no. of Hydrogen
X = no. of Halogens
N = no. of Nitrogen
DBE = (4+1) - (8/2)
DBE = 5-4
DBE = 1
It indicates the presence of 1 double bond in the possible structure.
Further structure can be identified by looking the peak values of the spectrum. So, we have,
2500 - 3300 = it indicates the presence of -COOH group
1720 = it indicates the (C=0) stretching
1200 = It indicates the (C-O) stretching
SO, the possible structure is
Butanoic Acid:
I have attached the structure of Butanoic Acid. Please refer to the attachment.
The answer is C. increasing the temperature of the liquid.
Increasing the temperature of the liquid also means that you are providing energy to the liquid, which makes the molecules overcome intermolecular attractive forces, move more constantly, and become gas molecules.
Hope this would help~