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3 years ago

Why does electronegativity decrease from right to left within a period?

Chemistry

1 answer:

Firlakuza [10]3 years ago

4 0

Explanation:

so, as you move down a group on the periodic table, the electronegativity of an element decreases because the increased number of energy levels puts the outer electrons very far away from the pull of the nucleus. electronegativity increases as you move from left to right across a period on the periodic table.

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In sublimation which state of matter is absent

Oliga [24]

Liquid :) it goes directly from a solid to a gas. Have a nice day!

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3 years ago

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The net charge on a sulfide ion (s2-) is -2. explain how this ion obtains its charge

Anestetic [448]

Sulfur is a group six element in period 3 with atomic number 16 and an electronic configuration of 2:8:6. Therefore, to attain a stable configuration it requires to gain two electrons forming an ion with a charge of -2. The negative charge is due to the gaining of electrons.

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3 years ago

For an alloy containing 50% cu and 50% ni, calculate the amounts of solid s and liquid l presents at 1300c. show that the total

iris [78.8K]

100 %cuni calculate the amounts of solid s and liquid

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3 years ago

A 1.10 mol sample of krypton gas is collected at a pressure of 427 mmHg and a temperature of 6.0°C. The volume of the sample is

Aleksandr [31]

Answer:

Volume = 44.96L

Explanation:

p = 427mmHg = 0.56atm

R = 0.08206

T 6°C = 279k

V = ?

n = 1.10 mol

using ideal gas equation

pv=nRT

0.56 x V = 1.10 x 0.08206 x 279

0.56 x V = 25.18

V = 25.18/0.56

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3 years ago

What is the mole fraction, X, of solute and the molality, m (or b), for an aqueous solution that is 15.0% NaOH by mass?

GalinKa [24]

Hello!

a) The mole fraction of solute of a 15% NaOH aqueous solution can be calculated in the following way:

First, we have to assume that we have 100 grams of solution. This will simplify the calculations.

Now, we know that this solution has 15 grams of NaOH and 85 grams of water. We can calculate the number of moles of each one in the following way:

$molesNaOH= 15 g NaOH*\frac{1molNaOH}{39,997 g NaOH}=0,3750 moles NaOH \\ \\ moles H_2O=85 gH_2O* \frac{1 mol H_2O}{18 g H_2O}=4,7222 moles H_2O$

To finish, we calculate the mole fraction by dividing the moles of NaOH between the total moles:

$X_{NaOH}= \frac{moles NaOH}{total moles}= \frac{0,3750 moles NaOH}{0,3750 moles NaOH+4,7222 molesH_2O} =0,073$

So, the mole fraction of NaOH is 0,073

b) The molality (moles NaOH/ kg of solvent) of a 15% NaOH aqueous solution can be calculated in the following way:

First, we have to assume that we have 100 grams of solution. This will simplify the calculations.

Now, we know that this solution has 15 grams of NaOH and 85 grams (0,085 kg) of water. We can calculate the moles of NaOH in the following way:

$molesNaOH= 15 g NaOH*\frac{1molNaOH}{39,997 g NaOH}=0,3750 moles NaOH$

Now, we apply the definition of molality to calculate the molality of the solution:

$mNaOH= \frac{moles NaOH}{kg_{solvent}}= \frac{0,3750 moles NaOH}{0,085 kg H_2O}=4,41 m$

So, the molality of this solution is 4,41 m

Have a nice day!

4 0

3 years ago