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3 years ago

10

If a store advertised a sale that gave customers a 1/4 discount,what is the fractional part of the original price that the custo

mer will pay

1 answer:

trasher [3.6K]3 years ago

3 0

3/4 as you are paying for what is not discounted

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lidiya [134]

We use the theory of Pythagoras because the triangle is right.

$AB {}^{2} = AC {}^{2} + BC {}^{2}$
since AB = AC = x
$8 {}^{2} = x {}^{2} + x {}^{2}$
$64 = 2x {}^{2}$
$32 = x {}^{2}$
$x = \sqrt{32}$
$x = \sqrt{16 } \times \sqrt{2}$
$x = 4 \sqrt{2}$

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3 years ago

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valina [46]

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Something weird was happening in space! Twenty-nine planets all bumped into each other planets once. How many bumps were felt th

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4 years ago

Prove that sinxtanx=1/cosx - cosx

maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

$\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}$

Taking the RHS, note

$\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}$

Remember that

$\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)$

Therefore,

$\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}$

Once

$\dfrac{\sin(x)}{\cos(x)} = \tan(x)$

Then,

$\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)$

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3 years ago

Use the points (0, 4) and (-2, 3) to find the slope of the line and give the equation of this line.

Sauron [17]

Answer:

Choice C: $m=\frac{1}{2}; y=\frac{1}{2} x+4$

Step-by-step explanation:

To find your slope do:

$\frac{y^2-y^1}{x^2-x^1}$

$\frac{3-4}{-2-0}=\frac{-1}{-2} =\frac{1}{2}$

that's how you get 1/2

4 is just the y-int.

6 0

2 years ago