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emmasim [6.3K]
3 years ago
5

What is the x-coordinate of the point that can be plotted on the graph between (6, 2) and (12, 4) that is part of this set of eq

uivalent ratios? Choose the point which has integer values for x and y.
Mathematics
2 answers:
vampirchik [111]3 years ago
8 0

Answer:

zero is the point between ( 6,

2 )and( 12,4)

nasty-shy [4]3 years ago
8 0

Answer:

8

Step-by-step explanation:

You might be interested in
ELECTRICITY The impedance in one part of a series circuit is 1 + 3j ohms and the impedance in another part of the circuit is 7 -
TiliK225 [7]

Answer:

Total impedance in circuit = 8 - 2j ohms

Step-by-step explanation:

Given:

Circuit one = 1 + 3j ohms

Circuit two = 7 - 5j ohms

Find:

Total impedance in circuit

Computation:

Total impedance in circuit = Circuit one + Circuit two

Total impedance in circuit = 1 + 3j + 7 - 5j

Total impedance in circuit = 8 - 2j ohms

5 0
3 years ago
What is the equation of the line that passes through the point (-2 0) and has a slope of 2
podryga [215]

The equation of the line will be y = 2x - 2.

<h3>What is an equation of the line?</h3>

A linear equation with a degree of one is referred to as a line equation. Two variables, x, and y are present in the equation of the line. The third parameter is the line's slope, which indicates the line's elevation.

The general form of the equation of the line is given as:-

y = mx + c

Given that the equation of the line is passing through the point ( -2,0) and the slope of the line is 2.

The equation of the line will be calculated as:-

y = mx + c

-2 = 0 + c

c = -2

y = mx + c

y = 2x - 2

Therefore, the equation of the line will be y = 2x - 2.

To know more about an equation of the line follow

brainly.com/question/18831322

#SPJ1

6 0
1 year ago
(x+15)^2 −10=0 i need solutions
Tasya [4]

Answer:

Step-by-step explanation:

(x-15)²=10

x-15=±√10

x=15±√10

or x=15+√10

and x=15-√10

4 0
3 years ago
4/6x 3/5 please help me will give brainliest
PilotLPTM [1.2K]

Answer:

0.4

Step-by-step explanation:

all I got to say is that the answer is 0.4 %100

6 0
3 years ago
Consider parallelogram ABCD with vertices at A(−10,6), B(−5.5,26), C(9.5,18), and D(5,−2). What is the perimeter, in units, of p
monitta

Given vertices of parallelogram ABCD:

A(−10,6), B(−5.5,26), C(9.5,18), and D(5,−2).

<u>Length of AB is :</u>

=\sqrt{\left(-5.5-\left(-10\right)\right)^2+\left(26-6\right)^2}= 20.5.

<u>Length of BC is : </u>

=\sqrt{\left(9.5-\left(-5.5\right)\right)^2+\left(18-26\right)^2} =17.

Note, opposite sides of a parallelogram are equal.

Therefore,

<em>Perimeter of parallelogram ABCD = 2 × Length of AB + 2 × Length of BC.</em>

Perimeter = 2 × 20.5 + 2 × 17

                 = 41 + 34

                 = 75 units.

<h3>Therefore, the perimeter of parallelogram ABCD is 75 units.</h3>
3 0
3 years ago
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