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Nesterboy [21]
3 years ago
11

How many crew members in all were in expeditions 7-12

Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0
7 is the answer brooo
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Novosadov [1.4K]

Answer: the answer is a

Step-by-step explanation: learned about it in 9th grade

5 0
3 years ago
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Solve the inequality. 4x+6<3x-5 A)x<1 B) x<11 C) x<-1 D)x<-11
klasskru [66]

4x + 6 < 3x - 5 is our given inequality

4x < 3x -11 by subtracting 6 on both sides of the inequality sign

x < -11 by subtracting 3x on both sides.


Thus, x < -11 -- choice D -- is the solution.

4 0
3 years ago
Two consecutive even integers have the following property. When the smaller integer is added to three times the larger integer,
polet [3.4K]
 let x be the first integer
 x+ 2 the second integer  ( two consecutive even ) 

smaller integer  added to three times the larger  <span>x + 3 ( x+2)
  </span>two less than five times the smaller  <span>5x - 2</span>

x + 3 ( x+2)   =  5x - 2

x+3x +6 = 5x -2 

x=8       
the first  integer = 8
the second is  x+2 =10 



4 0
3 years ago
Plss. pa answers ?<br><br>thanks po<br><br>​
Lana71 [14]

Answer:

<h3>Graph 3</h3>

Line starting at x = -2

  • <u>Domain</u>: x ≥ -2
  • <u>Range</u>: y ≥ 0
<h3>Graph 4</h3>

Vertical line

  • <u>Domain</u>: x = 3
  • <u>Range</u>: y = any real number
<h3>Graph 5</h3>

Quadratic function with negative leading coefficient and max value of 3

  • <u>Domain</u>: x = any real number
  • <u>Range</u>: y ≤ 3
<h3>Graph 6</h3>

Curve with non-negative domain and min value of -2

  • <u>Domain</u>: x ≥ 0
  • <u>Range</u>: y ≥ -2
<h3>Graph 7</h3>

Line with no restriction

  • <u>Domain</u>: x = any real number
  • <u>Range</u>: y = any real number
<h3>Graph 8</h3>

Quadratic function with positive leading coefficient and min value of 4

  • <u>Domain</u>: x = any real number
  • <u>Range</u>: y ≥ 4
<h3>Graph 9</h3>

Parabola with restriction at x = -4

  • <u>Domain</u>: x = any real number except -4
  • <u>Range</u>: y = any real number
<h3>Graph 10</h3>

Square root function with star point (2, 0)

  • <u>Domain</u>: x ≥ 2
  • <u>Range</u>: y ≥ 0
5 0
3 years ago
John runs a computer software store. Yesterday he counted 123 people who walked by the store, 56 of whom came into the store. Of
vaieri [72.5K]

Answer:

a) There is a 45.53% probability that a person who walks by the store will enter the store.

b) There is a 41.07% probability that a person who walks into the store will buy something.

c) There is a 18.70% probability that a person who walks by the store will come in and buy something.

d) There is a 58.93% probability that a person who comes into the store will buy nothing.

Step-by-step explanation:

This a probability problem.

The probability formula is given by:

P = \frac{D}{T}

In which P is the probability, D is the number of desired outcomes and T is the number of total outcomes.

The problem states that:

123 people walked by the store.

56 people came into the store.

23 bought something in the store.

(a) Estimate the probability that a person who walks by the store will enter the store.

123 people walked by the store and 56 entered the store, so T = 123, D = 56.

So

P = \frac{D}{T} = \frac{56}{123} = 0.4553

There is a 45.53% probability that a person who walks by the store will enter the store.

(b) Estimate the probability that a person who walks into the store will buy something.

56 people came into the store and 23 bought something, so T = 56, D = 23.

So

P = \frac{D}{T} = \frac{23}{56} = 0.4107

There is a 41.07% probability that a person who walks into the store will buy something.

(c) Estimate the probability that a person who walks by the store will come in and buy something.

123 people walked by the store and 23 came in and bought something, so T = 123, D = 23.

So

P = \frac{D}{T} = \frac{23}{123} = 0.1870

There is a 18.70% probability that a person who walks by the store will come in and buy something.

(d) Estimate the probability that a person who comes into the store will buy nothing.

Of the 56 people whom came into the store, 23 bought something. This means that 56-23 = 33 of them did not buy anything. So:

D = 33, T = 56

P = \frac{D}{T} = \frac{33}{56} = 0.5893

There is a 58.93% probability that a person who comes into the store will buy nothing.

8 0
3 years ago
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