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Dennis_Churaev [7]
3 years ago
9

April shoots an arrow upward at a speed of 80 feet per second from a platform 25 feet high. The pathway of the

Mathematics
1 answer:
zaharov [31]3 years ago
6 0

Answer:

The maximum height of the arrow is 125 feet.

Step-by-step explanation:

The pathway of the arrow can be represented by the equation,

h = -16t^2 +80t + 25 .....(1)

Where h is height in in feet and t is time in seconds.

It is required to find the maximum height of the arrow. For maximum height, \dfrac{dh}{dt}=0.

So,

\dfrac{d(-16t^2 +80t + 25)}{dt}=0\\\\-32t+80=0\\\\t=\dfrac{80}{32}\\\\t=2.5\ s

Put t = 2.5 s in equation (1). So,

h = -16(2.5)^2 +80(2.5) + 25\\\\h=125\ \text{feet}

So, the maximum height of the arrow is 125 feet.

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Answer:

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Step-by-step explanation:

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