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3 years ago

An equivalent expression for 12x+1 and 2(2x+5) please help

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

3 0

<h2>Answer:</h2>

8x+9

<h2>Step-by-step explanation:</h2>

12x+1 = 2(2x+5)

<h3><em><u>Handle the brackets first</u></em></h3>

12x+1 = 4x+10

<h3><em><u>Collect like terms</u></em></h3>

=8x+9

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Please help!!!!!!!!!!!!!!!

Sedaia [141]

Step-by-step explanation:

$\triangle{ABC}$ is similar to $\triangle{ADE}$ so we can write the ratio

$\dfrac{x}{6+4} = \dfrac{2}{6}$

Solving for x, we get

$x = \left(\dfrac{2}{6}\right)(10) = \dfrac{10}{3}$

6 0

2 years ago

What does the variable r represent in the equation 10r+4=8

Kryger [21]

Answer:

The value of variable r in the equation $10r+4=8$ is $\mathbf{r=0.4}$

Step-by-step explanation:

We need to find the value of variable r in the equation $10r+4=8$

Step 1: Write the equation

$10r+4=8$

Step 2: Subtract 4 on both sides

$10r+4-4=8-4\\10r=4$

Step 3: Divide both sides by 4

$\frac{10r}{10}=\frac{4}{10}\\r=0.4$

So, The value of variable r in the equation $10r+4=8$ is $\mathbf{r=0.4}$

3 0

2 years ago

Trina has two brothers. one brother is 7 years older than trina and the other brother is 7 years younger than trina. the product

AlladinOne [14]

(a) 95 = (x+7)*(x-7)

(b) 95 = (x+7)*(x-7)
Expand the brackets:
95 = x² -7x + 7x -49 = x² - 49
Subtract x² from both sides:
95-x² = -49
Subtract 95 from both sides:
-x²=-49-95
-x²= -144
Divide both sides by -1 to get rid of the negative numbers:
-x²/-1=-144/-1
x²=144
Take the square root of 144:
x = ± squareroot of 144
x = 12 or -12
x = 12 because you cannot have a negative age so Trina is 12 years old.

7 0

3 years ago

Plz help me with it

quester [9]

Answer: $\bold{\sqrt[4]{2} }$

<u>Step-by-step explanation:</u>

$\dfrac{1}{2}\sqrt[4]{32} =\dfrac{1}{2}\sqrt[4]{2\cdot 2\cdot 2\cdot 2\cdot 2}=\dfrac{1}{2}\cdot 2\sqrt[4]{2}=\boxed{\sqrt[4]{2} }$

4 0

3 years ago

Area triangles? it says show work so pls do

coldgirl [10]

$\large{\underline{\underline{\pmb{\sf {\color {blue}{Solution:}}}}}}$

Given,

Area = 225 yd²

Base = 30 yd

Height = [To be calculated]

To find:

The height of the given triangle.

We know that, area of a triangle is:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times h) \\ \\ \leadsto \frac{1}{2} \times 30h \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{30}h \\ \\ \leadsto1 \times 15h \\ \\ \leadsto \: h = 15 \: yd$

Therefore, the require height is 15 yd.

$\green\star$ Proof:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times 15) \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{450} \\ \\ \leadsto1 \times 225 \\ \\ area = 225 {yd}^{2}$

$\boxed{ \frak \red{brainlysamurai}}$

6 0

1 year ago

An equivalent expression for 12x+1 and 2(2x+5) please help​

An equivalent expression for 12x+1 and 2(2x+5) please help