Answer: The sum of the measures of the interior angles of a polygon is always 180(n-2) degrees, where n represents the number of sides of the polygon. The sum of the measures of the exterior angles of a polygon is always 360
-4(3m-3)+(-10+8m)
12m+12-1+8m
12m+8m = 20m
+12 -1= +11
answer: 20m+11
*note negative times a negative equals positive and negative times positive is negative
first: you multiply -4 by 3m which is -12m.
second: you multiply -4 by -3 which is +12
third: find the invisible which is 1. (located right here: +(1) (-10+8m)
fourth: multiply invisible 1 by -10 which is -10
fifth: multiply invisible one by +8m which is +8m
sixth: combine like terms
seventh: answer
Answer:
$95 per hour
Step-by-step explanation:
The total of charges is the sum of the cost of labor and the cost of parts. The cost of labor is the product of hours (5) and the cost per hour (x). Then the equation for total cost is ...
total cost = parts cost + hours cost
651 = 176 + 5x
475 = 5x . . . . . . . subtract 176
95 = x . . . . . . . . . divide by 5
The cost of labor per hour is $95.
This is a linear differential equation of first order. Solve this by integrating the coefficient of the y term and then raising e to the integrated coefficient to find the integrating factor, i.e. the integrating factor for this problem is e^(6x).
<span>Multiplying both sides of the equation by the integrating factor: </span>
<span>(y')e^(6x) + 6ye^(6x) = e^(12x) </span>
<span>The left side is the derivative of ye^(6x), hence </span>
<span>d/dx[ye^(6x)] = e^(12x) </span>
<span>Integrating </span>
<span>ye^(6x) = (1/12)e^(12x) + c where c is a constant </span>
<span>y = (1/12)e^(6x) + ce^(-6x) </span>
<span>Use the initial condition y(0)=-8 to find c: </span>
<span>-8 = (1/12) + c </span>
<span>c=-97/12 </span>
<span>Hence </span>
<span>y = (1/12)e^(6x) - (97/12)e^(-6x)</span>
Answer:
The clock face is divided into sixty equal parts, each minute. The minute hand is located on the 20 minute mark at 6:20, the hour hand located between the 30 minute mark and the 35 minute mark. When the minute hand goes all sixty minutes, the hour hand only moves five, so to figure out the location of the hour hand, we look at how much the hour has progressed, in this case 20 minutes, or one third of the hour. So the minute hand has moved one third of the way through the hour, so has the hour hand moved one third of the way through the five minutes, or, five thirds of a minute, which is one and two thirds minute, one minute forty seconds. That puts the hour hand at thirty minutes plus one minute and forty seconds—at 31min 40sec—which is 11min 40sec farther than the minute hand.
Step-by-step explanation:
