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Inessa05 [86]
3 years ago
7

some investments in the stock market have earned 10% annually, A, at this rate can be found using A=P(1.10)^n, where P is the in

itial value of the investment, and n is the number of years the money is invested. if $1,000 is invested in the stock market at this annual rate of return, what is the expected total value after 18 years? A) $4,054.47 B) $5,559.92 C) $18,700.00 D) $19,800.00
Mathematics
1 answer:
FromTheMoon [43]3 years ago
7 0
A=1000(1.1)^18
A=5559.92 ............
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a certain job can be done in 20 hours by 4 people. how many people are needed to do the same job in 10 hours?
maxonik [38]
If it takes 4 people to get a job done in 20 hours, then in 10 hours, it will take 2 people to complete the same job.
To find out how many people are needed to do this job in 10 hours, we can see that we got to 10 hours by dividing 20 by two so, to see how many people are needed to complete this same job in ten hours, we would just divide 4 people by 2 which is 2 people.
So, in conclusion, if it takes a certain job to be done in 20 hours by 4 people, then it would take 10 hours for that same job to be completed by 2 people.
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Ludmilka [50]
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8 0
3 years ago
PLEASE HELP......
Iteru [2.4K]
B is the answer i'm positive
7 0
3 years ago
An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de
Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have:

P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have

P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453

The sum of the probabilities is

P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981

8 0
3 years ago
In the year 2000, there were 5,000 people living in the town of Clairmont. By 2010, the population had grown to 5,600. What is t
kiruha [24]
I believe the answer is c ,BECAUSE... to find the change you take 5000 multiply it by the numbers that if aded would equal 5600 and 5000 times .12= 600, 5000 +600= 5600 hence the number of population in 2010.
 hope I helped 
6 0
3 years ago
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