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earnstyle [38]
3 years ago
13

Determine the length of the diagonals of the isosceles trapezoid below when KL= h+7 and UE= 4h-25

Mathematics
1 answer:
mina [271]3 years ago
6 0

Answer:

KL= 17.67 unit

UE = 17.67 unit

Step-by-step explanation:

Given:

Diagonals

KL= h+7

UE = 4h-25

Find:

Length of diagonals KL and UE

Computation:

We know that in isosceles trapezoid the length of diagonals are equal

So,

KL = UE

h+7 = 4h-25

3h = 32

h = 10.67

So,

KL= h+7

KL= 10.67+7

KL= 17.67 unit

UE = 4h-25

UE = 4(10.67)-25

UE = 17.67 unit

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Answer:

rise, run

Step-by-step explanation:

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6 0
3 years ago
2) A furlong is 1/8 of a mile. What part of a mile is 4 furlongs?
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Answer:

1/2 mile

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro
elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

You scored 1167 on Exam B, s:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1167 - 1031}{215}

Z = 0.632

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0
4 years ago
A year ago, Leila wanted to buy a necklace that cost $25.00. This year the same necklace cost $30.00. What was the percent incre
Delicious77 [7]

Answer:

20 %

Step-by-step explanation:

% Increase = Increase/Original value × 100 %

Data:

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This year = $30

Calculations:

   Increase =  This year - original

                  =         30       -      25

                  =                   $5

% Increase = 5/25 × 100 %

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The percent increase of the price of the necklace was 20 %.

4 0
3 years ago
A small hard drive measured 0.7553 centimeters across round to the nearest tenth
Alborosie

Answer:

0.8

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7 is in the tenth place since there is a 5 in the hundreds we round up to 8.

hope this helped =3

4 0
4 years ago
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