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3 years ago

What is the name of the National Outreach Project in FCCLA?

1 answer:

4 0

Answer:10. Describe Career Connection. Career Connection is an FCCLA national program that guides students to link their options and skills for success in families, careers and communities.

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PLEASE HELP!!!<br><br> Both Transverse and Longitudinal Waves transmit _______ and not ______.

qwelly [4]

I believe this is it

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3 years ago

Help meeeeeeeeeeee<br>what is the rheostat and what its ruleeee??

andre [41]

Answer:

<h2><u>Rheostat:</u></h2>

=> Rheostat is an electric device used as a variable resistance, like the regulator of the fan. It is used to change the electric resistance in the electric circuit.

<h2><u>Principle / Rule:</u></h2>

=> Rheostat works on the principle of Ohm’s law. Ohm’s law states that current in a circuit is inversely proportional to the resistance at the given temperature.

$\infty \infty \infty$

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3 years ago

If Noah runs three laps around a 200 meter track in two minutes, what is the average speed of Noah in m/s?

devlian [24]

• 3 laps of 200 meter track = 600 meters
• 600 meters ran in 2 minutes
• 2 minutes = 120 seconds
• 600 meters / 120 seconds = 5 m/s on average

6 0

3 years ago

What process primes a molecule to change in a way that increases its activity, produces motion, or does work

kirza4 [7]

Answer:

cellular respiration.

explanation: cellular respiration, the process by which organisms combine oxygen with foodstuff molecules, diverting the chemical energy in these substances into life-sustaining activities and discarding, as waste products, carbon dioxide and water.

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2 years ago

The speed of a particle moving in a circle 2.0 m in radius increases at the constant rate of 4.4 m/s2. At an instant when the ma

Law Incorporation [45]

Answer:

The speed of the particle is 2.86 m/s

Explanation:

Given;

radius of the circular path, r = 2.0 m

tangential acceleration, $a_t$ = 4.4 m/s²

total magnitude of the acceleration, a = 6.0 m/s²

Total acceleration is the vector sum of tangential acceleration and radial acceleration

$a = \sqrt{a_c^2 + a_t^2}\\\\$

where;

$a_c$ is the radial acceleration

$a = \sqrt{a_c^2 + a_t^2}\\\\a^2 = a_c^2 + a_t^2\\\\a_c^2 = a^2 -a_t^2\\\\a_c = \sqrt{a^2 -a_t^2}\\\\a_c = \sqrt{6.0^2 -4.4^2}\\\\a_c = \sqrt{16.64}\\\\a_c = 4.08 \ m/s^2$

The radial acceleration relates to speed of particle in the following equations;

$a_c = \frac{v^2}{r}$

where;

v is the speed of the particle

$v^2 = a_c r\\\\v= \sqrt{a_c r} \\\\v = \sqrt{4.08 *2}\\\\v = 2.86 \ m/s$

Therefore, the speed of the particle is 2.86 m/s

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4 years ago