Answer: 1 cal is 4.186 J, 1 kcal = 4186 J A : 1014 m , B 200 m
Explanation: A) Work done by climber is change in potential energy.
W = ΔEp = mgh = 67.0 kg· 9.81 m/s²· h = 160 kcal · 4186 J / kcal.
Solve h = 160 kcal · 4186 J / kcal /67.0 kg· 9.81 m/s² = 1014 m
B Energy is only 20 % : Then h = 0.20 ·160 kcal · 4186 J / kcal /67.0 kg· 9.81 m/s² = 200 m.
Actually, muscles also produce heat from most of the energy provided by food.
Here average speed for given motion is defined as ratio of total distance covered by total time
so here we can say
![v = \frac{d}{t}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bd%7D%7Bt%7D)
here total distance can be calculated by formula
distance = speed * time
![v = \frac{v_1*t_1 + v_2*t_2}{t_1 + t_2}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bv_1%2At_1%20%2B%20v_2%2At_2%7D%7Bt_1%20%2B%20t_2%7D)
here given that its average speed is v = 2.05 m/s
for first half let the time is "t " seconds and the speed for that is 2.01 m/s
and for next half time will be same and it is "t " seconds again
so by plug in all data in above equation we have
![2.05 = \frac{2.01* t + v* t}{t + t}](https://tex.z-dn.net/?f=2.05%20%3D%20%5Cfrac%7B2.01%2A%20t%20%2B%20v%2A%20t%7D%7Bt%20%2B%20t%7D)
![2.05 * 2 = 2.01 + v](https://tex.z-dn.net/?f=2.05%20%2A%202%20%3D%202.01%20%2B%20v)
![v = 2.09 m/s](https://tex.z-dn.net/?f=v%20%3D%202.09%20m%2Fs)
so its speed for next half must be 2.09 m/s
Answer:
the diffrence between the 2 are
aerobic respiration : requires oxogen, occurs in the mitochondria of cells, produces a lots of ATP per glucose molecule, and used when heart rate and breathing rate rise
anaerobic respiration : occurs in the cytoplasm of cells, dosen't require oxogen, used during the first 1 -2 minutes of exersise , and produces less ATP per glucose molecule
i hope this helps and i hope you had a great day
Answer:
1440 N
Explanation:
The electrostatic force between the two charges is given by:
![F=k\frac{q_1 q_2}{r^2}](https://tex.z-dn.net/?f=F%3Dk%5Cfrac%7Bq_1%20q_2%7D%7Br%5E2%7D)
where:
is the Coulomb's constant
is the value of each charge
r = 20.0 cm = 0.20 m is the separation between the charges
Substituting numbers into the equation, we find
![F=(9\cdot 10^9 N m^2 C^{-2} )\frac{(-8.00 \cdot 10^{-5}C)^2}{(0.20 m)^2}=1440 N](https://tex.z-dn.net/?f=F%3D%289%5Ccdot%2010%5E9%20N%20m%5E2%20C%5E%7B-2%7D%20%29%5Cfrac%7B%28-8.00%20%5Ccdot%2010%5E%7B-5%7DC%29%5E2%7D%7B%280.20%20m%29%5E2%7D%3D1440%20N)
Answer:
<h2>135,000 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 900 × 150
We have the final answer as
<h3>135,000 J</h3>
Hope this helps you