Answer:
I =
(K+5)
Explanation:
Given :
J = k+5
Now selecting a thin ring in the wire of radius "r" and thickness dr.
Current through the thin ring is
dI = J X 2πrdr
dI = (K+5) x 2πrdr
Now integrating we get
I = 
I = (K+5) 2π
I = (K+5) 2π 
I =
(K+5)
When we first dig into soil, it's nice and soft.( Depending on what soil it is; usually topsoil)
But when we go deeper into it, there are rocks and the soil is harder. There is bedrock at the bottom, subsoil in the middle, and topsoil at the top, which is where we walk.
Answer:
the number of grains in the ball is 274,848
Explanation:
Given that;
diameter = 0.5 mm
so radius r = 0.25 mm
first we determine the volume of the ball using the following equation;
V = 4/3×πr³
we substitute
V = 4/3×π(0.25)³
V = 0.06544 mm³
Now form table 1.1 "Grain sizes" a metal with grain size number of 12 has about 4,200,000 grains/mm³
so;
Number of grains N = 0.06544 × 4,200,000
N = 274,848 grains
Therefore, the number of grains in the ball is 274,848