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3 years ago

9

Agatha the snake is 50 centimeters long.3 years from now she will be 152 centimeters long and fully grown. If Agatha grows at co

nstant rate, how much does she grow in length each year

1 answer:

PIT_PIT [208]3 years ago

8 0

Answer: 34cm each year

Explanation:

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Someone please help with this

SSSSS [86.1K]

Answer:

<em>The new force is 2/3 of the original force</em>

Explanation:

<u>Coulomb's Law </u>

The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

$\displaystyle F=k\frac{q_1q_2}{d^2}$

Where:

$k=9\cdot 10^9\ N.m^2/c^2$

q1, q2 = the objects' charge

d= The distance between the objects

Suppose the first charge is doubled (2q1) and the second charge is one-third of the original charge (q2/3). Now the force is:

$\displaystyle F'=k\frac{2q_1*q_2/3}{d^2}$

Factoring out 2/3:

$\displaystyle F'=\frac{2}{3}k\frac{q_1*q_2}{d^2}$

Substituting the original force:

$F'=\frac{2}{3}F$

The new force is 2/3 of the original force

7 0

3 years ago

A thin-walled vessel of volume V contains N particles which slowly leak out of a small hole of area A. No particles enter the vo

LuckyWell [14K]

Answer:

$\frac{V}{2av}$

Explanation:

From the question we are told that

Volume V

Contains N particles

Leaks from a small hole of area A

Generally the equation for Flow rate is given as

Volume Flow Rate $V_r = A * v$

Mathematically we find the time taken to flow half way which is given by

$\frac{(V/2)}{A*v}$

Therefore the time taken is

$\frac{V}{2av}$

7 0

3 years ago

The conductive tissues of the upper leg can be modeled as a 40-cm-long, 12-cm-diameter cylinder of muscle and fat. The resistivi

ahrayia [7]

To calculate and solve the problem it is necessary to apply the concepts related to resistance and resistivity.

The equation that is responsible for relating the two variables is:

$R = \rho \frac{L}{A}$

Where,

R= Resistance of the conductor

$\rho =$ Resistivity of the conductor material

L = Length

A = Cross-sectional area of conductor

With the previous values the area of the muscle (Real Muscle-82%)is,

$A_m = (0.82)\pi r^2 = (0.82)\pi (12/2*10^{-2})^2$

$A_m = 9.274*10^{-3}m^2$

Using the equation from Resistance we have that at the muscle the value is:

$R_m = \rho \frac{L}{A}$

$R_m = \frac{13*(0.4)}{9.274*10^{-3}}$

$R_m = 560.70\Omega$

At the same time we can make the same process to calculate the resistance of the fat, then

$A_m = (0.18)\pi r^2 = (0.18)\pi (12/2*10^{-2})^2$

$A_m = 2.0357*10^{-3}m^2$

The resistance of the fat would be,

$R_f = \rho \frac{L}{A}$

$R_f = \frac{25*(0.4)}{2.0357*10^{-3}}$

$R_f = 4912.3\Omega$

Then the total resistance in a set as the previously writen, i.e, in parallel is:

$R=\frac{R_mR_f}{R_m+R_f}$

$R = \frac{(560.70)(4912.3)}{4912.3+560.70}$

$R = 502.62\Omega$

We can here apply Ohm's law, then

$I= \frac{V}{R}$

$I = \frac{1.5}{502.62}$

$I = 2.984*10^{-3}A$

$I = 2.984mA$

3 0

4 years ago

A machine is supplied Energy at a rate of 4000 W and does useful work at a rate of 3760 W. What is the efficiency of the machine

ICE Princess25 [194]

The efficiency of a machine is the ratio between the output power and the power in input:
$\epsilon = \frac{P_{out}}{P_{in}}$
in our problem, the output power is 3760 W while the input power is 4000 W, so the efficiency is
$\epsilon = \frac{3760 W}{4000 W} =0.94$
So the efficiency of the machine is 94%.

6 0

3 years ago

Read 2 more answers

A solar oven can be created by focusing the sun's rays to a point using a _________ mirror.

drek231 [11]

Concave mirror...as it focus the light at a given point..... concave mirror is converging !!!

7 0

3 years ago