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2 years ago

Five grams is equivalent to

Mathematics

2 answers:

Eduardwww [97]2 years ago

7 0

5grams=<span>0.0110231pound

1 teaspoon!

Hopefully this is what you were looking for :)</span>

mash [69]2 years ago

4 0

Five grams is equal to 1 teaspoon

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Evaluate each expression<br> 6! =<br> 3! • 2=<br> 31

Airida [17]

<h2><u>N-FACTORIAL!</u></h2>

<h3> $\mathbb{ \color{brown} \: PROBLEM } \: \: \bold{{ \color{brown}{1}}} :$ </h3>

$\mathcal{SOLUTION: }$

$\: \bold{ \red{6!}= 6×5×4×3×2×1= \boxed{ \bold{ \blue{720}}}}$

Therefore, <u>the value of 6! is 720</u>.

━┈─────────────────────┈━

<h3> $\mathbb{ \color{brown} \: PROBLEM } \: \: \bold{{ \color{brown}{2}}} :$ </h3>

$\mathcal{SOLUTION: }$

$\bold{3! \cdot 2! }\implies \bold{(3×2×1) \cdot( 2×1 )}$

$\: \: \: \: \: \: \: \: \: \: \: \: \implies \: \bold{ 6 \times 2} = \boxed{ \bold{ \blue{12}}}$

Therefore, <u>the value of the given expression is 12.</u>

━┈─────────────────────┈━

<h3><u>EXPLANATION</u><u>:</u></h3>

The mathematical symbol n! is read as "n factorial". The exclamation point "!" is read as factorial. And please remember or take note that 0! is equal to 1, and 1! is also equal to 1.

_______________∞_______________

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2 years ago

The number of students enrolled at a college is 14,000 and grows 6% each year.

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3 years ago

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Robert bough 3/4 pound of grapes and divided them into 6 equal portions.

insens350 [35]

Answer: The answer should be 0.125

Step-by-step explanation:

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2 years ago

A old computer model that cost $599(whole) is marked down 5%. How much money will the customer save (what is the discount only)?

Butoxors [25]

Answer:

The discount is 29.95

Step-by-step explanation:

599 x .05= 29.95

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3 years ago

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Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Darina [25.2K]

Answer:

Given definite integral as a limit of Riemann sums is:

$\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Step-by-step explanation:

Given definite integral is:

$\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}$

Substituting (2) in above

$f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Riemann sum is:

$= \lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

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3 years ago