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Eduardwww [97]
3 years ago
5

An endpoint of a line segment is (4,5) and the midpoint of the line segment is (3, -2). Find the other endpoint.

Mathematics
1 answer:
Dimas [21]3 years ago
4 0

Answer:

(-8,1)

Step-by-step explanation:

Using the equation for midpoints we can find:

\frac{(5+y)}{2} =3,  \frac{(4+x)}{2} =-2

y+5=6,      4+x=-4

y=1, x=-8

sry it's backwards

(-8,1)

Hope this helps!

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Write the domain and range of the graph below…
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Range:-4 is less then Y is less then 9. Domain: -5 is less then x is less then 4

Step-by-step explanation:

Look at where the lines end. That will help you find where the domain and ranges are.

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The distance from the floor of one level of the building to the floor of the level above it is 9 ft and 3/8 in. If the distance
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3 years ago
An automobile manufacturer has discovered that 20% of all the transmissions it installed in a particular style of truck are defe
Hatshy [7]

Answer:

0.148 = 14.8% probability that they will need to order at least one more new transmission

Step-by-step explanation:

For each transmission, there are only two possible outcomes. Either it is defective after a year of use, or it is not. The probability of a transmission being defective is independent of any other transmission. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% of all the transmissions it installed in a particular style of truck are defective after a year of use.

This means that p = 0.2

Sold seven trucks:

This means that n = 7

It has two of the new transmissions in stock. What is the probability that they will need to order at least one more new transmission?

This is the probability that at least 3 are defective, that is:

P(X \geq 3) = 1 - P(X < 3)

In which

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{7,0}.(0.2)^{0}.(0.8)^{7} = 0.2097

P(X = 1) = C_{7,1}.(0.2)^{1}.(0.8)^{6} = 0.3670

P(X = 2) = C_{7,2}.(0.2)^{2}.(0.8)^{5} = 0.2753

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2097 + 0.3670 + 0.2753 = 0.852

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.852 = 0.148

0.148 = 14.8% probability that they will need to order at least one more new transmission

6 0
3 years ago
jimmy is building a frame for his square garden he doesnt want the garden to be any bigger than 100ft squared what is the bigges
S_A_V [24]

100 divided by 4 so 25 feet on each side

8 0
4 years ago
Find the principal that will yield a simple interest of Rs 9000 in 5 years at a rate of 6% per annum.
damaskus [11]

9514 1404 393

Answer:

  ₹ 30000

Step-by-step explanation:

The simple interest formula is ...

  I = Prt . . . . . . principal P invested at rate r for t years

Fill in the values you know, and solve for the one you don't know.

  9000 = P(0.06)(5)

  9000/0.30 = P = 30000

The principal that will give ₹9000 in interest is ₹30000.

4 0
3 years ago
Read 2 more answers
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