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Sonja [21]
3 years ago
6

Solve 2^(6x-12)=(32)^(3x+12) for x.

Mathematics
2 answers:
Gre4nikov [31]3 years ago
8 0

Answer:

X = - 8

Let's solve your equation step-by-step.

26x−12=323x+12

Solve Exponent.

26x−12=323x+12

log(26x−12)=log(323x+12)(Take log of both sides)

(6x−12)*(log(2))=(3x+12)*(log(32))

6x−12=(

log(32)

log(2)

)*(3x+12)

6x−12=5*(3x+12)

6x−12=15x+60(Simplify both sides of the equation)

6x−12−15x=15x+60−15x(Subtract 15x from both sides)

−9x−12=60

−9x−12+12=60+12(Add 12 to both sides)

−9x=72

−9x

−9

=

72

−9

(Divide both sides by -9)

x=−8

sp2606 [1]3 years ago
7 0

Answer:The answer is x/52

Step-by-step explanation:

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A combination lock has a code consisting of 3 numbers, each of which can be 0 to 39, with numbers repeated. Jillian says that th
mestny [16]

Answer:

There are 64,000 possible codes. Jillian is incorrect, since he added the possible options in each trial, instead of multiplied them(he did 40+40+40 instead of 40*40*40).

Step-by-step explanation:

From 0 to 39, there are 40 numbers.

The code has three values:

V1 - V2 - V3

When we have n trials with m possible options, the total number of opitons is:

T = m^{n}

In this question:

3 trials(values), with 40 options. So

T = 40^{3} = 64000

There are 64,000 possible codes. Jillian is incorrect, since he added the possible options in each trial, instead of multiplied them(he did 40+40+40 instead of 40*40*40).

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3 years ago
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Helen [10]

Answer:△JKL∼△STU

When two triangles are similar , then their corresponding sides are proportional and Corresponding angles of one triangle is equal to corresponding angles of another Triangle.

The two Triangles can be similar by following Similarity axiom

Step-by-step explanation:

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3 years ago
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The quadrilateral is a rhombus.<br> If EF = 13 and DF = 18, find EH to the nearest tenth.
-Dominant- [34]

Answer:

EH = 9.4

Step-by-step explanation:

A rhombus is a quadrilateral with equal length of sides.

Given that,  EF = 13 and DF = 18

⇒ DH = HF = \frac{18}{2}

             = 9

The property that the diagonals of a rhombus are at right angle to each other.

Thus, applying the Pythagoras theorem, we have;

/hyp/^{2} = /adj1/^{2} + /adj2/^{2}

(EF)^{2} = (EH)^{2} + (HF)^{2}

(13)^{2} = (EH)^{2} + (9)^{2}

169 =  (EH)^{2} + 81

(EH)^{2} = 169 - 81

           = 88

EH = \sqrt{88}

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The length EH is 9.4

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3 years ago
Trapezoid ABFE is similar to trapezoid EFCD. What is the length of DC?
Murrr4er [49]

Answer:

6.75

Step-by-step explanation:

Find the relationship between the trapezoids. You can see that the top of trapezoid ABFE is 3 units and the top of EFCD is 4.5 units. 3 * 1.5 = 4.5, so t the sides of trapezoid EFCD are 1.5 times more than the sides of ABFE.

Now, you know the bottom of ABFE is 4.5, so the bottom of EFCD is 1.5 times longer because they are proportional, so you can do 4.5 * 1.5 = 6.75 units.

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